In the diagram of PARALLELOGRAM ABCD, segment BE is perpendicular to segment CED, segment DF is perpendicular to BFC and segment
CE is congruent to segment CF.
Prove ABCD is a rhombus.
Prove ABCD is a rhombus.
1 answer:
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Step-by-step explanation:
<h2>We first find the area of a trapezium and rectangular face</h2><h2>Fourmula to find the are of a trapezium is:</h2><h3>Area=1/2*(B+b)*h</h3><h3> =1/2*3.7*1.9</h3><h3> =3.515m²</h3><h2 /><h2>Since every rectangular face is different we gotta find each of them</h2><h3>Area1=4.8*2.1</h3><h3> =10.08 m²</h3><h3>Area2=4.8*1.4=6.72m²</h3><h3>Area3=4.8*2.3=11.05m²</h3><h3>Area4=4.8*1.9=9.12m²</h3><h3 /><h3>Now we find the area of the whole prism</h3><h3>Area=3.515*2+10.08+6.72+11.05+9.12</h3><h3>Area=44m²</h3><h2>Sorry my wireless went down!!!</h2><h2>Hope this helps and you already know what I would like to get</h2>