1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vitfil [10]
3 years ago
6

Object A has a mass m and a speed v, object B has a mass m/2 and a speed 4v, and object C has a mass 3m and a speed v/3. Rank th

e objects according to the magnitude of their momentum.
Physics
1 answer:
borishaifa [10]3 years ago
5 0
<h2>The rank is : P_B>P_A=P_C .</h2>

We need to rank the objects according to the magnitude of their momentum.

We know momentum ,P = m\times v{ here m is mass and v is velocity }

Momentum of object A , P_A = m v.

Momentum of object B , P_B= \dfrac{m}{2}\times4v=2\ mv.

Momentum of object C  , P_C= 3m\times\dfrac{v}{3}=mv.

Now, we can rank them in order of  their magnitude of momentum .

P_B>P_A=P_C.

Hence, this is the required solution.

Learn More :

Momentum

brainly.com/question/7957458

You might be interested in
Which single force acts on an object in freefall?
jok3333 [9.3K]
It has to be a)gravity
4 0
3 years ago
Read 2 more answers
You throw a baseball with a mass of 0.5 kg. The ball leaves your hand with a speed of 35 m/s. Calculate the kinetic energy. (SHO
mixas84 [53]

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy (K), in joules, is entirely translational, whose formula is:

K = \frac{1}{2}\cdot m\cdot v^{2} (1)

Where:

m - Mass, in kilograms.

v - Speed, in meters per second.

If we know that m = 0.5\,kg and v = 35\,\frac{m}{s}, then the kinetic energy of the baseball thrown by the player is:

K = \frac{1}{2}\cdot m \cdot v^{2}

K = 306.25\,J

The kinetic energy of the baseball is 306.25 joules.

6 0
3 years ago
______ is an offer to repair or replace a product if there is a problem with the product?
ANTONII [103]
<span>A warranty is an offer to repair or replace a product if there is a problem with the product. Warranties are written guarantee issued to the consumer by the manufacturer at the time of purchase, promising to repair or replace a faulty material. It is usually based on the premise that the product is free from defects in materials and workmanship. It claims that the manufacturer constructed the product out of proper materials, and would compensate the consumer should there be any defects. The period to file a claim typically varies. Some manufacturers place a 90 day period, some a year and a few, even more.</span>
6 0
4 years ago
On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik
RUDIKE [14]
(a)
The velocity of the meteorite just before hitting the ground is:
v=20 km/s=20000 m/s
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
\Delta K =  \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J

(b) 1 megaton of tnt is equal to 1 MT=4.2 \cdot 10^{15}J
To find to how many megatons the meteorite energy loss \Delta E
corresponds, we can set the following proportion
1 MT: 4.2 \cdot 10^{15}J=x: \Delta E
And so we find
x=  \frac{\Delta E}{4.2 \cdot 10^{15}J}  = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of \Delta E=0.162 MT=162 kT. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
1:13 kT=x:162 kT
And so we find
x= \frac{162 kT}{13 kT}=12.46
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
7 0
4 years ago
A soccer player runs up behind a 0.450-kg soccer ball traveling at 3.20 m/s and kicks it in the same direction as it is moving,
NISA [10]

To develop this problem it is necessary to use the concepts related to Impulse.

The impulse is defined as the change in velocity at the rate of mass, that is

L = m\Delta V,

Where,

m = Mass

\Delta V = Change in Velocity

This change in velocity can be expressed as,

L = m(v_2-v_1)

L = 0.45*(12.8 - 3.2)

L = 0.45*9.6

L= 4.32 Kg.m/s

Therefore the magnitude of the impulse is 4.32 Kg.m/s

7 0
3 years ago
Other questions:
  • What career uses advanced equipment such as light and electron microscopes to visualize complex images? (1 point)?
    9·1 answer
  • 3. Two charged boxes are 4 meters apart from each other. The blue box has a charge of +0.000337
    7·1 answer
  • Imagine Punch lives on the Earth at rest. Judy is traveling past the earth with a speed of 0.600 c. If a rocket moving in the sa
    6·1 answer
  • The resistivity of gold is 2.44 × 10-8 Ω · m at room temperature. A gold wire that is 1.8 mm in diameter and 11 cm long carries
    14·1 answer
  • What effect does force have on the motion of an object?
    5·1 answer
  • If love is the answer then what is the answer
    13·2 answers
  • 2. In each of A, B, C, &amp; D below, a sphere is moving from left to right next 20 points
    7·1 answer
  • A crane drops a 0.25kg steel ball onto a steel plate. The ball's speeds just before impact and after are 5.0m/s and 4.7m/s, resp
    6·1 answer
  • A soccer ball is kicked with an initial speed of 12m/s at a 30-degree angle above the horizontal. Calculate the horizontal veloc
    12·1 answer
  • 1) The unit of power is
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!