1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bess [88]
3 years ago
5

A 128.0-N carton is pulled up a frictionless baggage ramp inclined at 30.0∘above the horizontal by a rope exerting a 72.0-N pull

parallel to the ramp’s surface. If the carton travels 5.20 m along the surface of the ramp, calculate the work done on it by (a) the rope, (b) gravity, (c) the normal force of the ramp. (d) What is the net work done on the carton? (e) Suppose that the rope is angled at 50.0∘above the horizontal, instead of being parallel to the ramp’s surface. How much work does the rope do on the carton in this case?

Physics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

(A) 374.4 J

(B) -332.8 J

(C) 0 J

(D) 41.6 J

(E)  351.8 J

Explanation:

weight of carton (w) = 128 N

angle of inclination (θ) = 30 degrees

force (f) = 72 N

distance (s) = 5.2 m

(A) calculate the work done by the rope

  • work done = force x distance x cos θ
  • since the rope is parallel to the ramp the angle between the rope and

        the ramp θ will be 0

       work done = 72 x 5.2 x cos 0

       work done by the rope = 374.4 J

(B) calculate the work done by gravity

  • the work done by gravity = weight of carton x distance x cos θ
  • The weight of the carton = force exerted by the mass of the carton = m x g
  • the angle between the force exerted by the weight of the carton and the ramp is 120 degrees.

      work done by gravity = 128 x 5.2  x cos 120

      work done by gravity = -332.8 J

(C) find the work done by the normal force acting on the ramp

  • work done by the normal force = force x distance x cos θ
  • the angle between the normal force and the ramp is 90 degrees

       

         work done by the normal force = Fn x distance x cos θ

         work done by the normal force = Fn x 5.2 x cos 90

         work done by the normal force = Fn x 5.2 x 0

         work done by the normal force = 0 J

(D)  what is the net work done ?

  • The net work done is the addition of the work done by the rope,       gravitational force and the normal force

     net work done = 374.4 - 332.8 + 0 =  41.6 J  

(E) what is the work done by the rope when it is inclined at 50 degrees to the horizontal

  • work done by the rope= force x distance x cos θ
  • the angle of inclination will be 50 - 30 = 20 degrees, this is because the ramp is inclined at 30 degrees to the horizontal and the rope is inclined at 50 degrees to the horizontal and it is the angle of inclination of the rope with respect to the ramp we require to get the work done by the rope in pulling the carton on the ramp

work done = 72 x 5.2 x cos 20

work done = 351.8 J

You might be interested in
Below is the data from a gas law experiment comparing the pressure and the volume of a gas at a given temperature.
Wewaii [24]

Answer:

The combined gas equation relates three variables pressure, temperature and volume when the number of moles is constant.

The equation is PV / T = constant. Which is valid for a fixed number of moles of the gas.

You can derive the combined gas equation from the combination of Bolye's law, Charles' law and Gay-Lussac's law, which needs some algebra.

Explanation:

9 0
3 years ago
Read 2 more answers
8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?
Sidana [21]

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

q_1=q_2=+1C are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N

8 0
3 years ago
You are wearing earbuds or headphones to listen to your music but your family members can hear it as well. They tell you that it
allsm [11]

If it’s loud enough for your family to hear it, it’s best you turn it down. It could cause permanent damage to your ear drums if it’s loud enough and you could start to lose your hearing. So if your family were to tell you to turn it down, you should probably just turn it down!

5 0
3 years ago
Question 1 of 28
amm1812

Answer: D. They are the coldest stars.

Explanation:

5 0
2 years ago
Ruthford's theory was identified by
8090 [49]

Answer:

your mom

Explanation:

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is the accepted value of the speed of light through empty space?
    8·1 answer
  • When did they start using the word "Scrubbed" for launches?
    15·1 answer
  • Can I have help? I REALLY need it! PLEASE!
    7·1 answer
  • Connie teaches her children to call adults "sir" and "ma'am" and to say "please" and "thank you." These rituals are known as
    5·1 answer
  • Please Help!!!!! If you were in a completely weightless environment, would you need a force to make an object at rest start to m
    10·1 answer
  • 2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?
    11·2 answers
  • What is the magnitude of the electric field at the point if the electric potential in the region is given by V 2.00xyz2, where V
    13·1 answer
  • A box weighing 103 kg and a football weigh 0.41 and they dropped at the same time the top of a 98 m tall building.
    13·1 answer
  • A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distan
    7·1 answer
  • Need help due in 4 minutes
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!