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LuckyWell [14K]
3 years ago
8

Help plss .. Two bicyclists are accelerating forward in a straight line, and Biker 1 has less

Physics
1 answer:
castortr0y [4]3 years ago
4 0

Explanation:

Remember Newton's Second Law.

F=ma

If the force acting on both bikers is the same, we can look at the relationship between acceleration and mass.

If Biker 1 has a mass of 10kg and Biker 2 has a mass of 20kg, and both are being acted upon by a force of 100 N, let's see what that looks like. 100 = 10*a_1 \rightarrow a_1 = 100/10 = 10

100 = 20 *a_2 \rightarrow a_2 = 100/20 = 5

So, given the same force, an object with GREATER mass will have less acceleration.

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The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
  • B₀ is the magnetic field

I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

  • P is the power
  • A is the area crossed

So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J

I hope it helps you!

5 0
3 years ago
A physics lab group rolls a ball off a horizontal table with a speed of 1.6 m/s. the table is 1.2 m high. how far in the horizon
Brilliant_brown [7]

Answer:

0.784 m

Explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, with constant speed of v_0 = 1.6 m/s

- a vertical accelerated motion, with constant acceleration g=-9.8 m/s^2 towards the ground and initial position y_0 = 1.2 m

By looking at the vertical motion, we can find the time t at which the ball hits the ground, which is the time t at which the vertical position y becomes zero:

y(t)=0\\y(t)=y_0 +\frac{1}{2}gt^2\\0=y_0 +\frac{1}{2}gt^2\\t=\sqrt{-\frac{2 y_0}{g}}=\sqrt{-\frac{2\cdot 1.2 m}{-9.8 m/s^2}}=0.49 s

And now we can use the horizontal motion to find the total horizontal distance traveled during this time interval:

S_x = v t=(1.6 m/s)(0.49 s)=0.784 m

4 0
3 years ago
When a mule stops suddenly, the packages
Flauer [41]
The answer here would be the first law of motion. An object in motion will stay in motion unless acted upon by another force.
5 0
3 years ago
A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu
jekas [21]

The appropriate expression for the calculation of power by relating the angular energy in a given time.

In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

P=\tau\omega

Where

\tau = Torque

\omega =Angular speed

Our values are given by

\tau = 630Nm

\omega = 3200rev/min

The angular velocity must be transformed into radians per second then

\omega = 3200rev/min (\frac{2\pi rad}{60s})

\omega = 335.103rad/s

Replacing,

P=(630)(335.103)

P = 211.11*10^3W

P = 211.1kW

The average power delivered by the engine at this rotation rate is 211.1kW

5 0
3 years ago
Can somebody please answer this correctly I will give brainliest
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I think what’s wrong is that the paper clip isn’t connecting to the other thing on the bottom
8 0
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