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jolli1 [7]
2 years ago
15

F(x) = (3x + 6) (x - 3)²

Mathematics
1 answer:
Sever21 [200]2 years ago
5 0

f(x)= 3x³ - 18x +9

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Identity I: (a + b)² = a² + 2ab + b²

Identity II: (a – b)² = a² – 2ab + b²

Identity III: a² – b²= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x² + (a + b) x + ab

Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)

Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)

Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

f(x) = (3x + 6) (x - 3)²

      = ( 3x + 6) ( x - 3 )²

      = ( 3x + 6)( x² - 6x + 9)

      = 3x( x² - 6x + 9) + 6( x² - 6x + 9)

      = 3x³ - 6x² + 18x + 6x² - 36x +9

      = 3x³ - 18x +9

To learn more about algebraic expansions, refer to brainly.com/question/4344214

#SPJ9

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La opinión correcta es la de Camila que argumenta que la frecuencia relativa de la cara con el #6 será un valor cercano a 0,166.

<h3>Qué es la frecuencia relativa?</h3>

La frecuencia relativa es un término matemático que se utiliza en la estadística para referirse al número de veces que un evento se repite durante un experimento.

Por otra parte, es necesario aclara que la frecuencia relativa no se modifica en gran medida si se aumenta el número de veces de una prueba, debido a que la probabilidad de ocurrencia de este evento va a ser la misma.

De acuerdo a lo anterior, Camila tiene razón debido a que considera que el valor de la frecuencia relativa no se modifica en gran medida entre 300 o 600 lanzamientos de los dados.

Nota: Esta pregunta está incompleta porque no está la tabla. No obstante, la puedo responder basado en mi conocimiento previo.

Aprenda más sobre probabilidad en: brainly.com/question/16019390

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4 0
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5 0
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For `z_1 = 9"cis" (5pi)/(6)` and `z_2 = 3"cis" (pi)/(3)`, find `(z1)/(z2)` in rectangular form.
sammy [17]

Answer:

option D is correct, i.e. 3i

Step-by-step explanation:

Given are the complex number as Z₁ = 9 cis(5π/6) and Z₂ = 3 cis(π/3)

So magnitudes are r₁ = 9, and r₂ = 3

And arguments are ∅₁ = 5π/6, and ∅₂ = π/3

We know the formula for division of complex number is given as follows:-

If Z₁ = r₁ cis(∅₁) and Z₂ = r₂ cis(∅₂)

Then |Z₁ / Z₂| = (r₁/r₂) cis(∅₁ - ∅₂)

|Z₁ / Z₂| = (9/3) cis(5π/6 - π/3)

|Z₁ / Z₂| = 3 cis(5π/6 - 2π/6)

|Z₁ / Z₂| = 3 cis(3π/6)

|Z₁ / Z₂| = 3 cis(π/2)

|Z₁ / Z₂| = 3 cos(π/2) + 3i sin(π/2)

|Z₁ / Z₂| = 3*(0) + 3i*(1)

|Z₁ / Z₂| = 0 + 3i

|Z₁ / Z₂| = 3i

Hence, option D is correct, i.e. 3i

8 0
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