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jolli1 [7]
2 years ago
15

F(x) = (3x + 6) (x - 3)²

Mathematics
1 answer:
Sever21 [200]2 years ago
5 0

f(x)= 3x³ - 18x +9

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Identity I: (a + b)² = a² + 2ab + b²

Identity II: (a – b)² = a² – 2ab + b²

Identity III: a² – b²= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x² + (a + b) x + ab

Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)

Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)

Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

f(x) = (3x + 6) (x - 3)²

      = ( 3x + 6) ( x - 3 )²

      = ( 3x + 6)( x² - 6x + 9)

      = 3x( x² - 6x + 9) + 6( x² - 6x + 9)

      = 3x³ - 6x² + 18x + 6x² - 36x +9

      = 3x³ - 18x +9

To learn more about algebraic expansions, refer to brainly.com/question/4344214

#SPJ9

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Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
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3 years ago
If 3x is one factor of 3x^2-9x, what is the other factor?
Rudik [331]
The answer is:  " (x² − 3) " .
_________________________________
Explanation:
_________________________________

Given:  3x² <span>− 9x ;  factor out a "3x" ; 
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