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jolli1 [7]
2 years ago
15

F(x) = (3x + 6) (x - 3)²

Mathematics
1 answer:
Sever21 [200]2 years ago
5 0

f(x)= 3x³ - 18x +9

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Identity I: (a + b)² = a² + 2ab + b²

Identity II: (a – b)² = a² – 2ab + b²

Identity III: a² – b²= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x² + (a + b) x + ab

Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)

Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)

Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

f(x) = (3x + 6) (x - 3)²

      = ( 3x + 6) ( x - 3 )²

      = ( 3x + 6)( x² - 6x + 9)

      = 3x( x² - 6x + 9) + 6( x² - 6x + 9)

      = 3x³ - 6x² + 18x + 6x² - 36x +9

      = 3x³ - 18x +9

To learn more about algebraic expansions, refer to brainly.com/question/4344214

#SPJ9

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3 years ago
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
PLEASE HELP!!! GIVING BRAINLIEST
Anvisha [2.4K]

Answer:Column one answers:

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2:396

3.18

4.10

Column 2:

1. 490

2.396

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Column 3:

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Hope this helps if you need more then just ask

7 0
3 years ago
Evaluate the following algebraic expression, if (x = 5, y = 3)<br> x² +9y - 5
gladu [14]

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Step-by-step explanation:

simply substitute the constants with 5 and 3.

(5)^2 + 9(3) - 5 = 47

3 0
3 years ago
Read 2 more answers
Solve the simultaneous equations y=3x+2 and y=x+6
kogti [31]

Answer:

x=2

Step-by-step explanation:

y=3x+2

y=x+6

Since you're stating that, they both equal because equation is equated to equation 2 because of the Y.

Therefore, substitute into both equations as shown:

3x+2=x+6

3x-x=6-2  (bring 2 to the other side by subtracting 2 as well as x)

2x=4

2x/2=4/2  (dividing 2 on both sides to get rid off 2 in 2x)

x=2.

5 0
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