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irga5000 [103]
3 years ago
15

Consider a mystery compound having the formula MxTy. If the compound is not an acid, if it contains only two elements, and if M

is not a metal, which of the following is true about the compound?a.) It contains a polyatomic ion.b.) Its name ends in -ite or -ate.c.) Its name ends in -ic.d.) It is a binary molecular compound.
Chemistry
2 answers:
valkas [14]3 years ago
7 0

Answer:

d.) It is a binary molecular compound.

Explanation:

The compound in question has a formula M{x}T_{y}. The compound is not acidic in nature and the element 'M' is not a metal. This shows that the compound does not contain any metal. Based on the definition of a binary molecular compound as a compound comprising elements that are not metals. Therefore, the compound is obviously a binary molecular compound.

scoray [572]3 years ago
6 0

Answer:

The correct answer is d.) It is a binary molecular compound.

Explanation:

In the field of chemistry, binary compounds are undoubtedly one of the most important elements. When we talk about binary compounds we are referring to chemical type compounds that are characterized by having atoms of different chemical elements, such as sodium oxide (sodium and oxygen), phosphorus oxide (phosphorus and oxygen) or sulfur oxide (sulfur and oxygen), among many others. Binary compounds are more complex since they add different chemical elements and thus become a new element now formed by the sum of the characteristics of those joined elements.

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The density of sea water is 1.029 kilograms per liter. What is the density of
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Consider a galvanic cell based on the reaction Al^3+_(aq) + Mg_(s) rightarrow Al_(s) + Mg^2+ _(aq) The half-reactions are Al^3+
grin007 [14]

<u>Answer:</u> The standard cell potential of the cell is -0.71 V

<u>Explanation:</u>

The half reactions follows:

<u>Oxidation half reaction:</u>  Mg\rightarrow Mg^{2+}+2e^-;E^o_{Mg^{2+}/Mg}=-2.37V  ( × 3)

<u>Reduction half reaction:</u>  Al^{3+}(aq.)+3e^-\rightarrow Al(s);E^o_{Al^{3+}/Al}=-1.66V  ( × 2)

The balanced cell reaction follows:

2Al^{3+}(aq.)+3Mg(s)\rightarrow 2Al(s)+3Mg^{2+}(aq.)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation, we get:

E^o_{cell}=-2.37-(-1.66)=-0.71V

Hence, the standard cell potential of the cell is -0.71 V

8 0
3 years ago
What is the density of iron?
Maslowich

Answer:

7.874 g/cm³ is the density

5 0
3 years ago
Determine the number of significant digits in each number and list the specific significant digits. 1. 306,000 2. 0.0073 3. 39.9
Lelechka [254]

Answer:

1. 306,000: three significant figures because the last three zeros are not preceded by a decimal point.

2. 0.0073: two significant figures because the the leftmost zeros are not significant.

3. 39.9999: six significant figures because all these numbers are nonzero digits.

4. 25.00: four significant figures because right-handed zeros, after a decimal point, are significant.

5. 40,000,021: eight significant figures because intermediate zeros are significant.

6. 45,250.0: six significant figures because al the zeros are to the right of the nonzero digits.

7. 0.00011: two significant figures as well as #2.

8. 420.030700: nine significant figures because all the zeros are to the right of the first nonzero digits and after the decimal point.

Explanation:

Hello there!

In this case, by considering the given numbers, we can proceed as follows, by keeping in mind the rules for assigning significant figures:

1. 306,000: three significant figures because the last three zeros are not preceded by a decimal point.

2. 0.0073: two significant figures because the the leftmost zeros are not significant.

3. 39.9999: six significant figures because all these numbers are nonzero digits.

4. 25.00: four significant figures because right-handed zeros, after a decimal point, are significant.

5. 40,000,021: eight significant figures because intermediate zeros are significant.

6. 45,250.0: six significant figures because al the zeros are to the right of the nonzero digits.

7. 0.00011: two significant figures as well as #2.

8. 420.030700: nine significant figures because all the zeros are to the right of the first nonzero digits and after the decimal point.

Regards!

7 0
3 years ago
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