Answer:
1.93×10⁻³ mmoles/L of C₆Cl₆; 1.58×10⁻⁴ mmoles/L of C₁₂H₈Cl₆O; 3.51×10⁻³ mmoles/L of C₆H₆Cl₆
Explanation:
We have to find out the molar mass of each pesticide to calculate the moles, and then the milimoles
C₆Cl₆ → 12. 6 + 35.45 .6 = 284.7 g/m
C₁₂H₈Cl₆O → 12 . 12 + 8.1 + 35.45 .6 + 16 = 380.7 g/m
C₆H₆Cl₆ → 12.6 + 6.1 + 35.45 .6 = 290,7 g/m
Let's convert mg to g (/1000)
0.55 mg / 1000 = 5.5×10⁻⁴ g
0.060 mg / 1000 = 6×10⁻⁵ g
1.02 mg / 1000 = 1.02×10⁻³ g
Now we can know the moles (mass / molar mass)
5.5×10⁻⁴ g / 284.7 g/m = 1.93×10⁻⁶ moles of C₆Cl₆
6×10⁻⁵ g / 380.7 g/m = 1.58×10⁻⁷ moles of C₁₂H₈Cl₆O
1.02×10⁻³ g / 290,7 g/m = 3.51×10⁻⁶ moles of C₆H₆Cl₆
Milimoles = Mol . 1000
1.93×10⁻⁶ . 1000 = 1.93×10⁻³ mmoles of C₆Cl₆
1.58×10⁻⁷ . 1000 = 1.58×10⁻⁴ mmoles of C₁₂H₈Cl₆O
3.51×10⁻⁶ . 1000 = 3.51×10⁻³ mmoles of C₆H₆Cl₆
