Answer:
f(x) = 26500 * (0.925)^x
It will take 7 years
Step-by-step explanation:
A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.
To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.
Yes it is correct. You plotted the slope and initial rate value correctly and found the
point of intersection.
Formula : 2 x pie x radius
1. 2x3.14x3=18.84in
2.2x3.14x6=36.48yd
3.2x3.14x4=25.12ft
4.2x3.14x12=75.36yd
Answer:
The final answers are x = 10.385 OR x = -0.385
Step-by-step explanation:
Given the equation is x^2 -4 = 10x
Rewriting it in quadratic form as:- x^2 -10x -4 = 0.
a = 1, b = -10, c = -4.
Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)
x = ( 10 ± √(100 -4*1*-4) ) / (2*1)
x = ( 10 ± √(100 +16) ) / (2)
x = ( 10 ± √(116) ) / (2)
x = ( 10 ± 10.77 ) / (2)
x = ( 10 + 10.77 ) / (2) OR x = ( 10 - 10.77 ) / (2)
x = 20.77/2 OR x = -0.77/2
x = 10.385 OR x = -0.385
Hence, final answers are x = 10.385 OR x = -0.385