Answer: OK so Natural resources are not evenly distributed all over the world. Some places are more endowed than others — for instance, some regions have lots of water (and access to the ocean and seas). Others have lots of minerals and forestlands. Others have metallic rocks, wildlife, fossil fuels, and so on.The distribution of natural resources depends upon many physical factors like land, climate and altitude. The distribution of resources is unequal because these factors differ from place to place on this earth. Hope this helps have a nice night❤️
Explanation:
Water-rich solutions carrying metallic salts fill cracks and form <u>veins</u>.
I'll just list down the acidic, basic, and neutral salts.
ACIDIC
<span>THE CATION: is the conjugate acid of a weak base
THE ANION: Conjugate Base of A Strong Acid
</span>Ammonium Sulfate - <span>(NH₄)₂SO₄
</span>Ammonium Chloride - NH₄Cl
BASIC
<span>THE CATION: comes from the cation of a strong Base (i.e. Na+, K+, Li+)
The Anion: comes from the conjugate base of a weak acid
</span>Sodium Acetate - CH₃COONaSodium Phosphate - <span>Na₃PO₄
</span>Calcium Acetate - (CH₃COO)₂Ca
NEUTRAL
<span>THE CATION: comes from a strong base
THE ANION: comes from a strong acid
</span>Sodium Nitrate - NaNO₃
Barium Chloride - BaCl₂Potassium Chloride - KCl
Answer:
39.72 g
Explanation:
Given data:
Mass of CsF = 15.2 g
Mass of XeF₆ = 260 g
Mass of Cs[XeF₇] = ?
Solution:
Chemical reaction:
CsF + XeF₆ → Cs[XeF₇]
Number of moles of CsF:
Number of moles = mass/ molar mass
Number of moles = 15.2 g/151.9 g/mol
Number of moles = 0.1 mol
Number of moles of XeF₆ :
Number of moles = mass/ molar mass
Number of moles = 260 g/245.28 g/mol
Number of moles = 1.06 mol
Now we will compare the moles of Cs[XeF₇] with both reactants.
CsF : Cs[XeF₇]
1 : 1
0.1 : 0.1
XeF₆ : Cs[XeF₇]
1 : 1
1.06 ; 1.06
Number of moles of Cs[XeF₇] produce by CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].
Mass of Cs[XeF₇]:
Mass = number of moles × molar mass
Mass = 0.1 mol × 397.2 g/mol
Mass = 39.72 g
1) All the CO2 comes from the C24 H30 N3 O
2) To balance C from CO2 with C from C24, the ratio of cC24 H30 N3 O to CO2 is 24 / 1
3) Convert 1.20 g of CO2 to number of moles
number of moles = mass in grams / molar mass
mass = 1.20 g
molar mass = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
number of moles = 1.2 g / 44.01 g/mol = 0.0273 mol
4) proportion
1 mol C24 H30 N3 O / 24 mol CO2 = x / 0.0273 mol CO2
=> x = 0.0273 mol CO2 * 1 mol C24H30N3O / 24 mol CO2 = 0.00114 mol C24H30N3O
5) Convert 0.00114 mol C24H30N3O to grams
molar mass = 376.5 g/mol
mass = 0.00114 mol * 376.5 g/mol = 0.429 g
6) mass percent in the mixture
mass percent = (mass of lsd / mass of mixture) * 100 = (0.429g / 1.0g) * 100 = 42.9%
Answer: 42.9%
