Answer:
2.5 mole O2 should react (2 * 2.5) = 5.0 mole H2 but there is 6.0 mole H2. H2 remain in excess. O2 is the limiting reactant. mole of H2O formed = 2 * 2.5 = 5.0 mole.
The answer to this would be helium
The enthalpy change accompanying the reaction of 0.95 g of S is -11.85 kJ
<h3>Further explanation</h3>
Given
ΔH° for the reaction is -790 kJ
Required
The enthalpy change
Solution
Reaction
2S (s) + 3O₂(g) = 2SO₃ (g)
mol of S(MW=32 g/mol) :
For 2 mol S, the entalphy = -790kJ
The enthalpy change for 0.03 mol :
Answer:
Option D - 10,000 years ago in the Middle East
Answer:
for what I can see in the picture the volume is 155
Explanation: