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Bogdan [553]
1 year ago
5

Write the chemical symbols for three different atomic cations that all have 19 protons.

Chemistry
1 answer:
tamaranim1 [39]1 year ago
7 0

The chemical symbols for three different atomic cations that all have 19 protons : [Ca+] and [Sc2+] and [Ti3+]

Calcium:

Calcium have 20 electrons or it have 20 atomic number. Since an atom is a neutral species.

[Ca] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2)

After losing one electron atom gain positive charge and is become

[Ca+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

Scandium:

Scandium have 21 electrons or it have 21 atomic number. Since an atom is a neutral species.

[Sc] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2) (3d1)

After losing two electron atom gain positive charge and is become

[Sc2+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

Titanium:

Titanium have 22 electrons or it have 22 atomic number. Since an atom is a neutral species.

[Ti] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2) (3d2)

After losing three electron atom gain positive charge and is become

[Ti3+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

learn more about cation:

brainly.com/question/11095707

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Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

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