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1 year ago

Write the chemical symbols for three different atomic cations that all have 19 protons.

Chemistry

1 answer:

tamaranim1 [39]1 year ago

7 0

The chemical symbols for three different atomic cations that all have 19 protons : [Ca+] and [Sc2+] and [Ti3+]

Calcium:

Calcium have 20 electrons or it have 20 atomic number. Since an atom is a neutral species.

[Ca] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2)

After losing one electron atom gain positive charge and is become

[Ca+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

Scandium:

Scandium have 21 electrons or it have 21 atomic number. Since an atom is a neutral species.

[Sc] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2) (3d1)

After losing two electron atom gain positive charge and is become

[Sc2+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

Titanium:

Titanium have 22 electrons or it have 22 atomic number. Since an atom is a neutral species.

[Ti] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s2) (3d2)

After losing three electron atom gain positive charge and is become

[Ti3+] = (1s2) (2s2) (2p6) (3s2) (3p6) (4s1)

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$\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}$

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3 years ago

Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate

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Answer:

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(2S,3S)-2-ethoxy-3-methylpentane

Explanation:

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3 years ago

An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH

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Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

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The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

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Answer: $ClF$ will have a greater partial charge.

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