Answer:
0.375 M
Explanation:
molarity = number of moles of solute/ number of L solution = 3.00 mol/8.00 L=
= 0.375 mol/L = 0.375 M
Answer:
1.14 atm and 1.139 mol
Explanation:
The <em>total pressure</em> of the container is equal to the <u>sum of the partial pressure of the three gasses</u>:
- P = Poxygen + Pnitrogen + Pcarbon dioxide
- 2.50 atm = 0.52 + 0.84 + Pcarbon dioxide
Now we <u>solve for the pressure of carbon dioxide</u>:
- Pcarbon dioxide = 1.14 atm
To c<u>alculate the number of CO₂ moles </u>we use <em>PV=nRT</em>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 32 °C ⇒ 32 + 273.16 = 305.16 K
1.14 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305.16 K
To find out how many grams are in 4.65 moles of Al(NO₂)₃
Find out what the molar mass of Al(NO₂)₃ is
Al = 26.98 g/mol Al
N = 14 g/mol N
O = 16 g/mol O
Next, you have to look at the subscripts and figure out which they belong to, in this case:
Al = 26.98 g/mol Al
N₃ = 42 g/mol N₃
O₆ = 96 g/mol O₆
Finally, add the numbers together, so:
26.98 g/mol Al + 42 g/mol N₃ + 96 g/mol O₆ =
164.98 g/mol Al(NO₂)₃
Now, you have 4.65 mol Al(NO₂)₃ so
164.98 g/mol Al(NO₂)₃ × 4.65 mol Al(NO₂)₃ =
767.157 grams of Al(NO₂)₃
Do you still need the answer for these ? if so , i have them
Atomic mass is just protons plus neutrons
