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Kisachek [45]
3 years ago
12

Which has greater internal energy, 1 kg of water or 1 g of water, at the same temperature?

Chemistry
1 answer:
Natali5045456 [20]3 years ago
4 0

1kg of water has greater internal energy compared to 1g of water because 1kg of water has more mass.

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Why is it important to add coefficients and not change the subscripts when balancing a chemical equation?
Artemon [7]
Because of making the equestion to be more stable and form the best compound according to it's reactant.
5 0
3 years ago
If you were given two transparent liquids how would you determine which is pure and which is salt water
Tpy6a [65]
Based off the salt levels in each water.
8 0
2 years ago
Determine the specific heat of copper from the fact that 38 g of 80°C copper are needed to raise the temperature of 15 g of wate
mars1129 [50]
From the equation q=mCΔT, set the q of copper = to q of water,

So --- mCΔT(copper)=mCΔT(water).

mass (Cu - copper) = 38g
mass (H2O - water) = 15g
C (H2O) = 4.184 J/g*C
ΔΤ (H2O) = 33-22 = 11*C
ΔΤ (Cu) = 33-80 = -47*C (the final temp is the same for both materials - thermal equilibrium)
C (Cu) = ?

So --- 38(-47)C[Cu]=15(4.184)(11)
     --- C[Cu]=690.36/(-1786) = 0.3865 J/g*C, or 0.39 in 2 sig figs. (The negative goes away, because specific heats are usually positive)
5 0
3 years ago
Consider the ions of potassium (K) and sulfur (S), Write chemical formulas for all possible ionic compounds involving these ions
attashe74 [19]

The compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

<h3>What is an ionic compound?</h3>

An ionic compound is a commpound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.

Hence, the compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

Learn more about ionic compounds:brainly.com/question/9167977

#SPJ1

4 0
1 year ago
Read 2 more answers
Information related to a titration experiment is given in the balanced equation and table below.
Scorpion4ik [409]

Answer:

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

6 0
3 years ago
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