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ASHA 777 [7]
3 years ago
15

What is the molarity of a solution that contains 2 moles of solute in 4 liters of solution?

Chemistry
1 answer:
Nitella [24]3 years ago
8 0
The simple formula is C = n/V
n = mols
C = Concentration or Molarity
V = Volume in Liters.

n = 2
V = 4
C = 2 / 4
C = 0.5 mol/Litre

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13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂
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7 0
3 years ago
Read 2 more answers
2-A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%
aleksandrvk [35]

The molecular formula :

C₆H₁₄O₃PF

<h3>Further explanation</h3>

Given

39.10% carbon, 7.67% hydrogen, 26.11%  oxygen, 16.82% phosphorus, and 10.30% fluorine.

Required

The molecular formula

Solution

mol ratio :

C = 39.1 : 12 = 3.258

H = 7.67 : 1 = 7.67

O = 26.11 : 16 = 1.632

P = 16.82 : 31 = 0.543

F = 10.3 : 19 = 0.542

Divide by 0.542

C = 6

H : 14

O = 3

P = 1

F = 1

The empirical formula :

C₆H₁₄O₃PF

(The empirical formula)n = the molecular formula

(C₆H₁₄O₃PF)=184.1

(6.12+14.1+3.16+31+19)n=184.1

(184)n=184.1

n = 1

3 0
3 years ago
how many formula units of CaCl2 are in 111 g CaCl2? the molar mass of calcium chloride is about 111 g/mol
d1i1m1o1n [39]

There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.

<h3>What is a formula unit?</h3>

Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.

According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.

no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol

Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.

Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.

Learn more about formula units at: brainly.com/question/21494857

#SPJ1

5 0
2 years ago
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