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ASHA 777 [7]
3 years ago
15

What is the molarity of a solution that contains 2 moles of solute in 4 liters of solution?

Chemistry
1 answer:
Nitella [24]3 years ago
8 0
The simple formula is C = n/V
n = mols
C = Concentration or Molarity
V = Volume in Liters.

n = 2
V = 4
C = 2 / 4
C = 0.5 mol/Litre

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A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a
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Explanation:

please find the complete question in the attached file.

Mass of CH_3C0_2 H= 77 \ g \\\\

Molar mass of CH_3C0_2 H = 60.05 \  \frac{g}{mol} \\\\

No of moles in n_{CH_3CO_2H} = 77 \ g \times  \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}  

                                          = 1.28 \ mol \ CH_3CO_2H

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The molar mass of water (H_2O)= 18.02 \  \frac{g}{mol}

moles of water n_{H_2O}:

= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O

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X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\

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gavmur [86]

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