Answer:
Explanation:
1) Vanadium (IV) → V⁺⁴
Carbonate → CO₃⁻²
So , Vanadium (IV) Carbonate = V₂(CO₃)₄ or V(CO₃)₂
2) Tin (II) = Sn⁺²
Nitrite = NO₂⁻
So, Tin (II) Nitrate = Sn(NO₂)₂
3) Cobalt (III) = Co⁺³
Oxide = O⁻²
So , Cobalt (III) Oxide = Co₂O₃
4) Titanium (II) = Tn⁺²
Acetate = CH₃COO⁻
So , Titanium (II) Acetate = Tn(CH₃COO)₂ or Tn(C₂H₃O₂)₂
5) Vanadium (V) = V⁺⁵
Sulfide = S⁻²
So , Vanadium (V) Sulfide = V₂S₅
6) Chromium (III) = Cr⁺³
Hydroxide = OH⁻
So , Chromium (III) Hydroxide = Cr(OH)₃
7) Lithium = Li⁺
Iodide = I⁻
So , Lithium Iodide = LiI
8) Lead (II) = Pb⁺²
Nitride = N⁻³
So , Lead (II) Nitride = Pb₃N₂
9) Silver = Ag⁺
Bromide = Br⁻
So , Silver Bromide = AgBr
Answer:
What is the molarity of a solution containing 5.00 moles of kcl in 2.00L of solution? Molarity= moles of solute/volume of solution in litre , so the problem looks like this : 7/. 569 , which is equivalent to 12.302 M .
<span>Mg + O2 > MgO. In reactant side, 2 O atoms and 1 Mg are present. In product side, 1 Mg and O atoms are present. Put 2 in product side to balance O atoms and 2 at Mg in reactant side to balance Mg atoms. Therefore the balanced equation becomes, 2Mg + O2 ----> 2MgO. Hope it helps.</span>
Answer:
i think that the wet cloth will keep the coolness inside the water instead of evaporating and getting warm
Explanation:
