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torisob [31]
3 years ago
11

You carefully drop a stone into a beaker full of water. The stone sinks to the bottom and water spills out. What can you say abo

ut the weight of the displaced water
Chemistry
1 answer:
lara [203]3 years ago
6 0

Answer:

The weight of the displaced water is equal to the upthrust acting on the stone which is less than the weight of the stone thus the stone sinks to the bottom of the beaker. This is according to the Archimedes principle which states that when an object is partially or wholly immersed in a fluid  the weight of the displaced fluid is equal to the upthrust acting on the object.

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Aspirin is a weak organic acid whose molecular formula is HC9H7O4. An aqueous solution of aspirin is prepared by dissolving 3.60
garri49 [273]

Answer:

Ka = 3.50x10⁻⁴

Explanation:

First, we need to convert the unit of 3.60 g/L to mol/L:

C_{C_{9}H_{8}O_{4}} = 3.60 \frac{g}{L}*\frac{1 mol}{180.16 g} = 0.0200 mol/L

The reaction dissociation of aspirin in water is:

C₉H₈O₄  +  H₂O  ⇄  C₉H₇O₄⁻ + H₃O⁺    

0.02 - x                        x             x

The constant of the above reaction is:

Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]}

Ka = \frac{x^{2}}{0.02 - x}

To find Ka we need to find the value of x. We know that pH = 2.6 so:

pH = -log[H_{3}O^{+}]

2.6 = -log(x)

x = 2.51 \cdot 10^{-3} M = [H_{3}O^{+}] = [C_{9}H_{7}O_{4}^{-}]

Now, the concentration of C₉H₈O₄ is:

C_{C_{9}H_{8}O_{4}} = 0.02 - 2.51 \cdot 10^{-3} = 0.018 M

Finally, Ka is:

Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]} = \frac{(2.51 \cdot 10^{-3})^{2}}{0.018} = 3.50 \cdot 10^{-4}

Therefore, the Ka of aspirin is 3.50x10⁻⁴.

       

I hope it helps you!

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Answer:

is it 26.98

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