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Harrizon [31]
2 years ago
11

The most common elemental form of nitrogen is ______. multiple choice question. n2 n n3 n4

Chemistry
1 answer:
Elden [556K]2 years ago
5 0

The most common elemental form of nitrogen is N2 (option 1).

<h3>What is nitrogen?</h3>

Nitrogen is a chemical element (symbol N) with an atomic number of 7 and atomic weight of 14.0067. It is a colorless and odorless gas.

As earlier said, nitrogen is a gaseous element at room temperature. This means that it naturally exists as a gas in the atmosphere.

The chemical formula of elemental nitrogen is N, however, it exists as atmospheric nitrogen with the chemical formula of N2.

N2 denotes that two atoms of nitrogen have chemically combined to form a nitrogen molecule.

Learn more about nitrogen at: brainly.com/question/11426882

#SPJ1

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tekilochka [14]

Answer:

<u>0.78 L</u>

Explanation:

From Boyle's Law :

P₁V₁ = P₂V₂

Here :

  • P₁ = 2.00 atm
  • V₁ = 1.56 L
  • P₂ = 4.00 L

Solving :

  • V₂ = P₁V₁ / P₂
  • V₂ = 2 x 1.56 / 4
  • V₂ = 1.56 / 2
  • V₂ = <u>0.78 L</u>
5 0
2 years ago
Explain how you know that no new element with an atomic number less than 100 will be discovered
Klio2033 [76]
The elements are identified by its aomic number and they are placed in the periodic table in ascending order of atomic number.

There is one unique element for a given atomic number.

For example, atomic number 1 identifies Hydrogen and there cannot be another different element with the same atomic number.

All the elements with atomic numbers from 1 to 118 have been discovered. So, you know that there is not room for new products with atomic number equal or less than 118.
3 0
3 years ago
Is the Peruvian flower angiosperm or gymnosperm
professor190 [17]

Answer:

angiosperm

Explanation:

7 0
3 years ago
Read 2 more answers
How many protons are in an atom of oxygen?<br><br><br> 6<br><br> 8<br><br> 16<br><br> 24
Monica [59]

Answer:

8 Protons

Explanation:

4 0
3 years ago
If it requires 23.4 milliliters of 0.65 molar barium hydroxide to neutralize 42.5 milliliters of nitric acid, solve for the mola
rodikova [14]
Volume Ba(OH)2 = 23.4 mL in liters : 

23.4 / 1000 => 0.0234 L

Molarity  Ba(OH)2 = 0.65 M

Volume HNO3 = 42.5 mL in liters:

42.5 / 1000 => 0.0425 L

number of moles Ba(OH)2 :

n = M x V

n = 0.65 x 0.0234 

n = 0.01521 moles of Ba(OH)2

Mole ratio :

<span>Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O
</span>
1 mole Ba(OH)2 ---------------- 2 moles HNO3
 0.01521 moles ----------------- moles HNO3

moles HNO3 = 0.01521 x 2 / 1

moles HNO3 = 0.03042 / 1

= 0.03042 moles HNO3

Therefore:

M ( HNO3 ) = n / volume ( HNO3 )

M ( HNO3 ) =  0.03042 / 0.0425

M ( HNO3 ) = 0.715 M

5 0
3 years ago
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