Equation :
PbF2 ------> Pb2+ + 2F-
Solubility product is given as:
Ksp = [Pb2+][F-]^2
let x = [Pb2+]
Ksp = x(2x)^2 = 4(x)^3 = 4(2.08*10^-3)^3
Ksp = 3.60*10^-8
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>
Given
80% 127I, 17% 126I, and 3% 128I.
Required
The average atomic mass
Solution
The elements in nature have several types of isotopes
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%
Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128
Atomic mass of Iodine = 101.6 + 21.42 + 3.84
Atomic mass of Iodine = 126.86 amu
Answer:
2C2H18 + 13O2 → 4CO2 + 18H2O (I balanced your equation)
Products - CO2 & H20
"c. Number the chain of carbons, starting with the end nearest the multiple bond."
This choice means that the carbon atoms determine the name of the hydrocarbonsThank you for your question. Please don't hesitate to ask in Brainly your queries.
A) Energy is released during the formation of the bond.
Explanation:
During the formation of a chemical bonds between two hydrogen atoms, energy is always released during the formation of this bond type.
Bond formation process is usually exothermic and energy is released during the formation of the bond.
- Bond breaking process is an endothermic process in which energy is absorbed from the surrounding.
- Whenever a bond is broken, the bond energy value is positive but when a bond is formed, the bond energy value is given a negative sign.
For a bond formation process in which hydrogen atoms are bonded covalently, energy is usually released.
Learn more:
Enthalpy changes brainly.com/question/10567109
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