You can titrate a sample of the vinegar with a known standard of NaOH. The pH at the equivalence point is determined by the hydrolysis of the salt
Answer:
None of the species in the equation have undergone either oxidation or reduction
Explanation:
The easiest way to see if oxidation or reduction has happened is to compare oxidation numbers of each and every species before and after the reaction.
Calcium is two before the reaction and two after the reaction
Hydrogen is -1 before the reaction and -1 after the reaction
Sodium is one before the reaction and one after the reaction
Iodine is -1 before the reaction and -1 after the reaction.
For an oxidation to happen an increase in oxidation number has to happen.
For a reduction to happen, a decrease in oxidation number has to happen. None have happened
Answer:
b. 1.5 atm.
Explanation:
Hello!
In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:
Now, if we introduce the stoichiometry, and the change in the pressure 
we can write:
Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:
Thus, the final pressure is:
Therefore the answer is b. 1.5 atm.
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The compounds that can dissociate in water from the options given below are;
Ba(NO3)2
CaSO4
Mg3(PO4)2
<h3>What is dissociation of compounds?</h3>
Dissociation of compound is the process by which compounds degraded into smaller unit which can also recombine to form larger one in another condition.
When ionic compounds dissociate in water, the water molecules separate the ionic crystal. This is because of the attraction between the positive and negative ions in the crystal.
Therefore, The following compounds dissociate in water.
Ba(NO3)2
CaSO4
Mg3(PO4)2
Learn more about dissociation of compounds here.
brainly.com/question/11835372
Answer:
calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.
1 mol contains 310 grams
2.3*10^-4 moles contain 2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.
If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.
