Which of the following would be expected to have the highest viscosity? CH3CH2OH, HOCH2OH, CH3CH2CH3

Chemistry

1 answer:

zaharov [31]3 years ago

5 0

Answer: Out of the given options $HOCH_{2}OH$ is expected to have the highest viscosity.

Explanation:

The resistance occurred in the flow of a liquid substance is called viscosity.

More stronger is the intermolecular forces present in a substance more will be its resistance in its flow. Hence, more will be its viscosity.

For example, $HOCH_{2}OH$ has strong intermolecular hydrogen bonding than the one's present in $CH_{3}CH_{2}OH$ and $CH_{3}CH_{2}CH_{3}$ . This is because two-OH groups are present over here.

Thus, we can conclude that out of the given options $HOCH_{2}OH$ is expected to have the highest viscosity.

You might be interested in

A) For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry a

Aleks04 [339]

Answer:

Explanation:

According to Bronsted-Lowry acids or base theory , the reagent capable of giving hydrogen ion or proton will be acid and that which accepts hydrogen ion or proton will be base .

C₉H₇N + HNO₂ ⇄ C₉H₇NH⁺ + NO₂⁻

If K > 1 , reaction is proceeding from left to right .

Hence HNO₂ is giving H⁺ or proton and C₉H₇N is accepting proton to form

C₉H₇NH⁺ .

Hence HNO₂ is bronsted acid and C₉H₇N is bronsted base .

B )

when K < 1 , reaction above proceeds from right to left . That means

C₉H₇NH⁺ is giving H⁺ so it is a bronsted acid and NO₂⁻ is accepting H⁺ so it is a bronsted base .

Hence , NO₂⁻ is a bronsted base and C₉H₇NH⁺ is a bronsted acid .

4 0

3 years ago

The atomic number of magnesium is 12 this is also the number of which of the following