If you remove thermal heat from the reaction the reaction will slow down. meaning that there will be fewer collisions occurring between the particles.
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Answer:
200 g C₆H₁₂O₆
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
1 M C₆H₁₂O₆
1 L of solution
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
<u>Step 3: Find moles of solute</u>
1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L
x = 1 mol C₆H₁₂O₆
<u>Step 4: Convert</u>
<u />
= 180.18 g C₆H₁₂O₆
<u>Step 5: Check</u>
<em>We are given 1 sig figs. Follow sig fig rules and round.</em>
180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆
Answer:
Hydrogen Bonding
Explanation:
Hydrogen bonding occurs between the positive dipole of one water molecule with the negative dipole of another. It is an intermolecular force that gives water its unique properties such as: high boiling point, high specific heat, cohesion, adhesion, and density.
Answer:
The phase transition from a solid to a gas.
Explanation:
Entropy is related to the moles of gases available. The more gaseous moles, the higher the entropy.
<em>Identify the process in which the entropy increases.</em>
- <em>the phase transition from a solid to a gas</em>. YES. There are more gaseous moles available so entropy increases.
- <em>a decrease in the number of moles of a gas during a chemical reaction</em>. NO. This causes a decrease in entropy.
- <em>the phase transition from a liquid to a solid</em>. NO. There is almost no change in the entropy in this process.
- <em>the phase transition from a gas to a liquid</em>. NO. There is a decrease in entropy in this process.
- <em>the phase transition from a gas to a solid</em>. NO. There is a decrease in entropy in this process.
