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1 year ago

A(n) acid or base will dissociate completely in water, whereas a(n) acid or base dissociates very little in water.

1 answer:

5 0

A(n) strong acid or base will dissociate completely in water, whereas a(n) weak acid or base dissociates very little in water.

Strong acids are defined as any acid that completely dissociates into ions. It is a weak acid if dissociation is less than 100%.

Strong bases are defined as any acid that completely dissociates into ions. It is a weak base if dissociation is less than 100%.

Not every acid or base ionizes or dissociates to the same degree. This supports the claim that not all acids and bases have the same ability to produce H+ and OH- ions in solution.

The adjectives "strong" and "weak" describe how strong an acid or base is. The ability of acidic and basic solutions to conduct electricity is referred to as strong and weak.

Strong electrical conductivity indicates that an acid or base is a strong acid or base. A weak acid or base is one that conducts electricity only slightly.

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At Which points in this graph is bone growing at the faster rate?

Vikki [24]

The rate of growth is faster in the (10 - 14) age group and slows down after the age of 14. After the age of 16 the growth is the slowest

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3 years ago

Read 2 more answers

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

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3 years ago

How many molecules of BH3 are in 14.32 grams of BH3?

kkurt [141]

Answer:

6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.

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3 years ago

A sample of an ionic compound NaA, where A- is the anion of a

vitfil [10]

Answer:

a) Kb = 10^-9

b) pH = 3.02

Explanation:

a) pH 5.0 titration with a 100 mL sample containing 500 mL of 0.10 M HCl, or 0.05 moles of HCl. Therefore we have the following:

[NaA] and [A-] = 0.05/0.6 = 0.083 M

Kb = Kw/Ka = 10^-14/[H+] = 10^-14/10^-5 = 10^-9

b) For the stoichiometric point in the titration, 0.100 moles of NaA have to be found in a 1.1L solution, and this is equal to:

[A-] = [H+] = (0.1 L)*(1 M)/1.1 L = 0.091 M

pKb = 10^-9

Ka = 10^-5

HA = H+ + A-

Ka = 10^-5 = ([H+]*[A-])/[HA] = [H+]^2/(0.091 - [H+])

[H+]^2 + 10^5 * [H+] - 10^-5 * 0.091 = 0

Clearing [H+]:

[H+] = 0.00095 M

pH = -log([H+]) = -log(0.00095) = 3.02

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3 years ago

Some animals hunt by _______ or sneaking up on their prey. It a nine letter word and there a m in the second place

guajiro [1.7K]

Answer:

Some animals hunt by <em>Camouflage</em> or sneaking up on their prey.

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2 years ago