Answer : The shape of the fluoroform molecule is Tetrahedral.
Explanation :
First we have to calculate the Hybridization of the molecule by formula,
![\text{Number of electrons} = \frac{1}{2}[V+H-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5BV%2BH-C%2BA%5D)
where,
V = Number of valence shell electron in central atom
H = Number of neighboring monovalent atom
C = charge of cation
A = charge of anion
The central atom in this molecule is Carbon, it has 4 electrons in their valence shell.
The neighboring monovalent atoms are one Hydrogen atom and three Fluorine atom.
There is no charge of cation and anion on the given molecule.
V = 4
H = 1 Hydrogen atom + 3 fluorine atom = 4
C = 0
A = 0
By the above hybridization formula, we get
= 4
The number of electron pair = 4
The number of lone pair = 0
The number of electrons is 4, this means that the hybridization is
and the geometry of the molecule is Tetrahedral.
The geometry of the molecule is shown below.
The volume in liters occupied by 22.6 g of I₂ gas at STP is 1.99 L (answer A)
<u><em>calculation</em></u>
Step: find the moles of I₂
moles= mass÷ molar mass
from periodic table the molar mass of I₂ is 253.8 g/mol
moles = 22.6 g÷253.8 g/mol =0.089 moles
Step 2:find the volume of I₂ at STP
At STP 1 moles =22.4 L
0.089 moles= ? L
<em>by cross multiplication</em>
={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L
Neon, Helium, Krypton, Xenon, Argon
Answer:
Q1) Mole ratio would be 1:1