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andrey2020 [161]
3 years ago
12

Which is an issue that governments must consider before passing conservation policies? urbanization implications cost to impleme

nt conservation policies desertification implications cost to implement deforestation
Chemistry
2 answers:
bixtya [17]3 years ago
8 0

Answer:

urbanization implications

environmental implications

benefit versus the cost

Explanation:

Conservation involves preservation of organisms and their natural habitat to encourage biodiversity and reduces the risk of extinction.

Urbanization involves the loss of organism’s natural habitat due to deforestation and building of more structures such as buildings and road structures.Government must consider before passing conservation policies if the urbanization will have a bigger impact than conservation.

Environmental implications is also taken into account as the environment is where we live and makes it very important to ensure there are no negative effects.

The benefit and cost are weighed and the one with a lower cost and higher benefit is usually embraced.

Tanya [424]3 years ago
8 0

Answer:

B) Cost to implement conservation policies

Explanation:

i took the test edg2020

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Help! Will mark brainliest! Explain why a mechanical wave does not exist in a vacuum.
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Do bases lose or gain hydrogen ions?<br><br><br>Help :-)
kodGreya [7K]

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3 years ago
Suppose that 100 grams of water at 50.0°C is placed in contact with 200 grams of iron at 30.0°C. The final
wel

Answer:

The answer would be 1.5 kJ.

Explanation:

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4 0
2 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
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