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Vesna [10]
3 years ago
9

A gravel can be broken down into different kinds of substances by physical processes. No chemical reactions are needed to separa

te different parts of gravel into pure substances. This is because gravel is a(n)
compound
element
homogeneous mixture
heterogeneous mixture
Chemistry
2 answers:
butalik [34]3 years ago
6 0

answer:

heterogenous mixture

Explanation:

lukranit [14]3 years ago
5 0

Answer:

heterogenous mixture

Explanation:

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how many electrons does it take to fill the mos formed from the combination of the 3s orbitals of two atoms?
Musya8 [376]

The number of electrons it take to fill the mos formed from the combination of the 3s orbitals of two atoms simply is 14 electrons.

<h3>How electrons are distributed in the 3s orbitals.</h3>

The 3s orbital possess two different spherical nodes which is highly connected with the principal quantum number. In order words, it has 2 radial nodes. Also the shape of the 3s orbital is spherical in shape.

That being said, from the context of the above given task, the number of electrons which fill the mos formed from the combination of the 3s orbitals of two atoms is fourteen electrons.

However, the electron configuration of an atom simply is the arrangement of electrons in the electron shell or orbit of the atom of that element.

In conclusion, it can be deduced from above s orbital has a maximum of two electrons and this energy increases as the orbitals increases.

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7 0
1 year ago
How are the formulas and names of ionic compounds written
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3 0
3 years ago
Magnesium (Mg) has two electrons in its outer shell. Mg will _____.
bogdanovich [222]
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7 0
3 years ago
A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

4 0
3 years ago
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