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Zolol [24]
2 years ago
7

What would your estimate be for the age of the universe if you measured hubble's constant to be 11 kilometers per second per mil

lion light-years?
Physics
1 answer:
vredina [299]2 years ago
6 0

By using Hubble's constant H₀, the estimated age of the universe would be 27,269,816,110  years.

As we know that the age of the universe is something near to the time the galaxies needed to reach their current distance:

T = D/V

where T is the time the galaxies needed, D is distance and V is speed.

By using Hubble's law we can use the equation

V = H₀*D

where H₀ is Hubble's constant

By combining these 2 equations, we get

T = D/(H₀*D) = 1/H₀ .............(A)

In conclusion, the age of the universe is something near the inverse of Hubble's constant.

From the question above, we know that:

H₀ = 11 km/s/Mly

By using equation A we get

T = 1/(11 km/s*Mly)

T = (1/11)  s*Mly/km

Convert 1 million light-years to km by (1 ly = 9.461*10^12 km)

T = (1/11) s*Mly/km

T = (1/11)*9.461*10^18 s

T = 8.6009*10^17 s

Convert to years by (1 year = 3.154*10^7 s)

T = 8.6009*10^17 s

T = (8.6009*10^17 s/3.154*10^7 s)* 1 yea

T = 27,269,816,110 years.

Learn more about Hubble's constant at: brainly.com/question/27051032

#SPJ4

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Two parallel plates that are initially uncharged are separated by 1.7 mm, have only air between them, and each have surface area
yaroslaw [1]

Answer:

5.63\cdot 10^{-6} C

Explanation:

The capacitor of a parallel-plate capacitor is given by:

C=\epsilon_0 \frac{A}{d}

where

A is the area of each plate

d is the separation between the plates

\epsilon_0 is the vacuum permittivity

The energy stored in a capacitor instead is given by

U=\frac{1}{2}\frac{Q^2}{C}

where

Q is the charge stored in each plate

Substituting the expression we found for C inside the last formula,

U=\frac{1}{2}\frac{Q^2 d}{\epsilon_0 A}

And re-arranging it

Q=\sqrt{\frac{2U\epsilon_0 A}{d}}

Now if we substitute

d=1.7 mm=0.0017 m\\A=16 cm^2 = 16\cdot 10^{-4} m^2\\U = 1.9 J

We find the charge stored on the capacitor:

Q=\sqrt{\frac{2(1.9)(8.85\cdot 10^{-12})(16\cdot 10^{-4})}{0.0017}}=5.63\cdot 10^{-6} C

7 0
3 years ago
HELP!! ALL MY POINTS WILL BE GIVEN
Marta_Voda [28]

Answer:

-6 m/s^2

Explanation:

30 - 90 = -60

-60 / 10 = -6

If acceleration was constant, it will be -6 m/s^2

5 0
2 years ago
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Answer:

1. a

2. a [im iffy on this but 95% positive its this]

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3 0
3 years ago
Coming to the bottom of a mountain, a skier moving with speed v collides with a barrier and is brought to a stop in an amount of
IRISSAK [1]

Answer:

Explanation:

Impulse of a force is measured by force x time or F X t

Impulse also equals change in momentum or

F x t = m v₂ - m v₁

The given case is as follows

in the first case

F x t = mv - o = mv

F = mv / t

in the second case

F₁ x 4 t = mv

F₁ = 1/4 x mv /t

F₁ = F / 4

option a) is correct .

iii )

In the last case

F₂ X t = m v/2 -0

F₂ = 1/2 x mv / t

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8 0
3 years ago
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solong [7]

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

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For object B on the earth, W = 25 N,

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m = \frac{25}{10}

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Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

5 0
3 years ago
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