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3 years ago

Calculate the mmoi of a tire that weighs 15.0 kg and has a radius of 30.0 (treat it as a hoop )

Physics

1 answer:

lys-0071 [83]3 years ago

6 0

Answer:

Kinetic Energy and Work: The mass moment of inertia of the wheel about ... The wheel is made from a 5-kg thin ring and two 2-kg slender ... determine the maximum angular velocity of the wheel if it is ... velocity of the pulley at the instant the 20-lb weight moves ... The spool has a mass of 40 kg and a radius of gyration of.

Explanation:

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Use the information and model to answer the following question.

olga_2 [115]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

4. Two forces act on a 2 kg object as shown. What is the magnitude of the acceleration of the object?

aleksandrvk [35]

The resultant force on the object is

∑ F = 〈0, 8〉 N + 〈6, 0〉 N = 〈6, 8〉 N

which has a magnitude of

F = √((6 N)² + (8 N)²) = √(100 N²) = 10 N

By Newton's second law, the acceleration has magnitude a such that

F = m a

10 N = (2 kg) a

a = (10 N) / (2 kg)

a = 5 m/s²

so the answer is B.

4 0

3 years ago

In a belly-flop diving contest, the winner is the diver who makes the biggest splash upon hitting the water. the size

ad-work [718]

The second diver have to leap to make a competitive splash by 4.08 m high.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

PE = mgh

where, g = 9.81 m/s²

Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.

The potential energy of the first diver must be equal to the second diver.

P.E₁ = P.E₂

m₁gh₁ = m₂gh₂

Substitute the vales, we have

136 x 3 = 100 x h₂

h₂ = ₂4.08 m

Thus, the second diver need to leap by 4.08 m high.

Learn more about potential energy.

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7 0

2 years ago

The Earth's electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC a

castortr0y [4]

Answer:

The final kinetic energy is $K = 1.1 \ J$

Explanation:

From the question we are told that

The electric field is $E = 100 \ V/m$

The charge on the object is $q = 4.5 mC = 4.5 *10^{-3} \ C$

The mass of the object is $m_o = 68 \ g = 0.68 \ kg$

The distance moved by the object is $d = 1.0 \ m$

The workdone on the object by the fields is mathematically represented as

$W = [qE + mg]d$

Now this workdone is equivalent to the final kinetic energy so

$K = W = [qE + mg]d$

substituting values

$K = W = [4.5*10^{-3 } *100 + 0.68 * 9.8]* 1$

$K = 1.1 \ J$

8 0

3 years ago

Determine the inductive reactance for a 50 mH inductor that is across a 15 volt, 400 Hz source.

tresset_1 [31]

Answer:

Inductive reactance is 125.7 Ω

Explanation:

It is given that,

Inductance, $L=50\ mH=0.05\ H$

Voltage source, V = 15 volt

Frequency, f = 400 Hz

The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :

$X_L=2\pi fL$

$X_L=2\pi \times 400\ Hz\times 0.05\ H$

$X_L=125.66\ \Omega$

$X_L=125.7\ \Omega$

So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.

8 0

3 years ago