A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer: 27,24,21....
d=24-27=-3 a=27
let nth term=0
a+(n-1)d=0
27+(n-1)-3=0
(n-1)-3=-27
n-1=9
n=10
Step-by-step explanation:
561 x 103 = 57783, so the place value of the 1 will be 3. :)
Answer:
i think n = 4
Step-by-step explanation:
3(n+7) = 33
3n+21 = 33
3n = 12
n = 4
Answer:
where is the question at
Step-by-step explanation:
