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2 years ago

13

A snowmobile manufacturer claims that it’s newest that it’s newest model is 15% lighter than last years model. If this years mod

el weighs 799 lb, how much did last years model weigh

1 answer:

Andreas93 [3]2 years ago

8 0

Answer:

it should weigh 919.

Step-by-step explanation:

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there is a ratio of 5 girls to 3 boys in the chorus. there are 24 in the chorus. how many girls are in the chorus

Yuki888 [10]

Answer:

15 girls

Step-by-step explanation:

5 + 3 = 8

24 ÷ 8 = 3

3 · 5 = 15

Check:

3 · 5 = 15

3 · 3 = 9

9 + 15 = 24

I hope this helps!!

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3 years ago

There are 8 pencils in a package how many packages will be needed for 28 children if each child gets 4 pencils

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7 packages will be needed

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Nathlan lives on the 8th floor

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3 years ago

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What would D,E, I need help with these questions

Ilia_Sergeevich [38]

Answer:

D - 43°

E - 43°

Step-by-step explanation:

In squares all sides are equal, which means one of these angles are given and neither one leave the square, so 43° would be the degree of each angle inside this square.

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3 years ago

X/x-2 + x-1/x+1= -1<br> Can someone walk me through the steps of this problem? Much appreciated. :)

stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1$

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

$\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1$

Add the numerators and keep the denominator so that there is now one fraction:

$\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1$

Simplify the numerator by expanding the brackets:

$\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1$

$\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1$

Simplify the denominator by expanding the brackets:

$\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1$

Multiply both sides by the denominator of the left side:

$\implies 2x^2-2x+2=-1(x^2-x-2)$

Simplify and move everything to the left side:

$\implies 2x^2-2x+2=-x^2+x+2$

$\implies 3x^2-3x=0$

Factor:

$\implies 3x(x-1)=0$

Therefore:

$\implies 3x=0 \implies x=0$

$\implies x-1=0 \implies x=1$

Therefore, x = 0 or x = 1

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2 years ago

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