Biodiversity provides functioning ecosystems that supply oxygen, clean air and water, pollination of plants, pest control, wastewater treatment and many ecosystem services. Recreation—many recreational pursuits rely on our unique biodiversity , such as birdwatching, hiking, camping and fishing.
Yes, biodiversity is something that I personally value and everyone should.
Biodiversity supports human and societal needs, including food and nutrition security, energy, development of medicines and pharmaceuticals and freshwater, which together underpin good health. It also supports economic opportunities, and leisure activities that contribute to overall wellbeing.
Yes, I wish that more people thought like this.
The answer is b scientific law because it would have had to be tested many times for it to become a scientific law in the first place.
Answer:
B. 1.1
(I just counted the measurements)
Answer:
1). Xeroderma pigmentation.
2). Ataxia-telangiectasia.
Explanation:
DNA repair processes include all the processes, which help in identification and correction of errors or damages in DNA. Defects in DNA repair mechanisms that increase risks for developing cancers and various other disorders. Two conditions related to faulty DNA repair are:
1). Xeroderma pigmentation (XP): XP can be defined as a genetic disorder, due to mutations in genes involved in repair processes. It leads to severe sunburn and freckling due to sun exposure, dry skin and skin pigmentation. People having xeroderma pigmentation are prone for skin cancer.
2). Ataxia-telangiectasia (AT): AT is caused bu mutation in ATM gene (ataxia-telangiectasia mutated) gene, which in involved in nucleotide-excision repair pathway. It leads to severe disability in children and increases risk for developing lymphomas and leukemia.
Answer:
2.25%.
Explanation:
The recombination progeny occur due to the crossing over of the homologous chromosomes. The linked gene is 30 map units apart and the recombination frequency is 30.
If a plant of Ab/aB is selfed then the progeny obtained is as follows: Ab – parental – 35%, aB – parental – 35%, AB – recombinant – 15% and ab – recombinant – 15%. The cross between the F2 progeny with aabb is ( 0.15 × 0.15) = 0.0225 or 2.25%.
Thus, the answer is option (A).
