Answer:
A. The bobsled acceleration is 3.14 m/s²
Explanation:
Given:
Mass of the bobsled (m) = 132 kg
Force of push (F) = 450.0 N
Force of friction (f) = 35 N
Let the acceleration of the bobsled be 'a' m/s².
Now, as per Newton's second law, the net force acting on a body is equal to the product of mass and acceleration.
Net force acting on the bobsled is equal to the difference of applied force and friction and is given as:

Now, from Newton's second law,

Plug in all the values given and solve for 'a'. This gives,

Therefore, the acceleration is 3.14 m/s². So, option (A) is correct.