A push or a pull is called _____. User: The metric unit of force is the ____

What would the weight of an astronaut be on Saturn if his mass is 68 kg and acceleration of gravity on Saturn is 10.44 m/s2? Ple

alex41 [277]

Here's the part you need to know:

   (Weight of anything) =

   (the thing's mass)
times
       (acceleration of gravity in the place where the thing is) .

   Weight = (mass ) x (gravity) .

That's always true everywhere.
You should memorize it.

For the astronaut on Saturn . . .

   Weight = (mass ) x (gravity) .

   Weight = (68 kg) x (10.44 m/s²)

   = 709.92 newtons .
__________________________________

On Earth, gravity is only 9.8 m/s².
So as long as the astronaut is on Earth, his weight is only

   (68 kg) x (9.8 m/s²)

   = 666.4 newtons .

Notice that his mass is his mass ... it doesn't change
no matter where he goes.

But his weight changes in different places, because
it depends on the gravity in each place.

4 0

3 years ago

Calculate the average force that must be exerted on a 0.145 kg baseball in order to give it an acceleration of 130 m/s^2. (round

r-ruslan [8.4K]

Answer:

18.9 N or 19 N rounded

Explanation:

m = 0.145 kg

a = 130 m/s^2

F = ma = (0.145 kg)(130 m/s^2) = 18.9 N

7 0

3 years ago

Read 2 more answers

If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an

ss7ja [257]

Distance , d = a+b $t^2$

The unit of d is in meter and t is in seconds.

So the unit of a a must be meter.

Now we have unit of b $t^2$ is meter.

So unit of b* $second^2$ = meter

Unit of b = meter/ $second^2$

So unit of a = m and unit of b = m/ $s^2$ .

8 0

3 years ago

As an object accelerates to a speed close to the speed of light, which of the following stays the same?

kirill115 [55]

A. Speed of light (Apex)

6 0

3 years ago

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The speed at which a light aircraft can take off is 120 km/h. (A) What is the minimum constant acceleration required for the pla

kondor19780726 [428]

Answer:

A) a = 2.31[m/s^2]; B) t = 14.4 [s]

Explanation:

We can solve this problem using the kinematic equations, but firts we must identify the data:

Vf= final velocity = take off velocity = 120[km/h]

Vi= initial velocity = 0, because the plane starts to move from the rest.

dx= distance to run = 240 [m]

$v_{f} ^{2} =v_{i} ^{2}+2*g*dx\\where:\\v_{f}=120[\frac{km}{h} ]*\frac{1hr}{3600sg} * \frac{1000m}{1km} =33.33[m/s]\\\\Replacing\\33.33^{2}=0+2*a*(240)\\ a=\frac{11108.88}{2*240}\\ a=2.31[m/s^2]\\$

To find the time we must use another kinematic equation.

$v_{f} =v_{i} +a*t\\replacing:\\33.33=0+(2.31*t)\\t=\frac{33.33}{2.31}\\ t=14.4[s]$

7 0

3 years ago

A push or a pull is called _____. User: The metric unit of force is the _____.

A push or a pull is called _. User: The metric unit of force is the _.