Question

A Downs cell operating at 77.0 A produces 31.0 kg of Na.(a) What volume of Cl₂(g) is produced at 1.0 atm and 540.°C?

Answer 1

Volume of Cl₂(g) is produced at 1.0 atm and 540.°C=4.5×10^4 L

As per the evenly distributed response

2NaCl (g) ----> 2Na(l)+ Cl2(g)

Calculate the amount of Cl2 that was formed as indicated below:

Moles of Cl2 = 31.0 kg of Na x (1000* 1 * 1 / 1*23* 2)

                   = 673.9 mol

P is equal to 1.0 atm, and T is equal to 813.15 K

when converted to Kelvin by multiplying by a factor of 273.15.

Using Cl2 as an ideal gas, determine the in the following volume:

volume = nRT/P

= 673.9 * 0.0821 * 813.15/ 1

=4.5×10^4 L

As a result, the volume of Cl2 under the given circumstances =4.5×10^4 L

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