Insulator! I hope this helps! Pls mark mine the brainliest;)
(1) MO₂(s) + C(s) → M(s) + CO₂ (g), ΔG₁ = 288.9 kJ/mol
(2) C(s) + O₂(g) → CO₂(g), ΔG₂ = -394.4 kJ/mol
By adding both equations 1 + 2 we get the coupled reaction:
MO₂(s) + 2 C(s) + O₂(g) → M(s) + 2 CO₂(g)
ΔG⁰ = ΔG₁ + ΔG₂
= 288.9 + (-394.4) = -105.5 kJ/mol = -105500 J/mol
Temperature T = 25 + 273.15 = 298.15 K
Molar gas constant R = 8.314 J/mol.K
K =

=
= 3.05 x 10¹⁸
<span>a) movement of heat through space </span>
Answer: pOH = 4.68
Explanation:
pOH = 14 - pH
pH = - Log [H+]
= - Log [4.8 x 10^-10]
= -(-9.32)
pH =+9.32
Therefore, pOH= 14 - 9.32
= 4.68