Answer:
c maybe sorry if its wrong
Explanation:
Answer:
Here's what I get
Explanation:
(a) Intermediates
The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).
(b) Relative Stabilities
The relative stabilities decrease in the order shown.
N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.
(c) Relative reactivities
The relative reactivities would be
C₆H₅-NH₂ > C₆H₅-OCH₃ > C₆H₅-NHCOCH₃
35°c is equal to 95°f
To do this multiply 35 and 1.8
35 x 1.8=63
Now add 32
Resulting in the answer 95
(The equation for to solve for c and f is c1.8+32=f
Answer:
by having positive and negative ends and stronger intermolecular forces of attraction.
Explanation:
hope this helps
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and im sorry if the answer is wrong