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polet [3.4K]
3 years ago
12

How are elements identifies in terms of their atoms?

Chemistry
2 answers:
Zina [86]3 years ago
8 0
Protons,neutrons,electrones,mass number and model are a few.
i hope this helped
-Dominant- [34]3 years ago
6 0
<span>they are identified by the number of protons they have in the nucleus which = their electrons. </span>
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Which structure assist with cell ur respiration?
Alexandra [31]

Answer:

Mitochondria

Explanation:

Mitochondria are organelles whose membranes are specialized for aerobic respiration.

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3 years ago
What is not true about radiation? it travels out in all directions from its source. it is one of three methods of heat transfer.
Alika [10]
The answer is the last one (it needs a medium through which to travel) it is not true about radiation. A radiation is the emission of energy in the form of waves or particles through space or through a material medium. This includes; electromagnetic radiation, such as a radio wave, microwaves, visible light, x rays, and gamma radiation. 
6 0
3 years ago
Read 2 more answers
If the density of a metal bar is 3.47 g/mL and volume is 30 mL, calculate the mass of the metal bar in grams (g). Show the steps
Hitman42 [59]

Answer:

m=104.1g

Explanation:

Hello,

In this case, considering that the density is considered as the quotient of the mass and volume:

\rho =\frac{m}{V}

We can easily compute the mass by solving for it as follows:

m=V*\rho =30 mL*3.47g/mL\\\\m=104.1g

Best regards.

7 0
3 years ago
What is the kinetic energy of a 25 kg object moving at a velocity of 2.5 m/s?
vovangra [49]

Answer:

<h2>78.13 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 25 \times  {2.5}^{2}  \\  = 12.5 \times 6.25 \\  = 78.125 \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>78.13 J</h3>

Hope this helps you

6 0
3 years ago
What is the partial pressure (in atm) of CO₂ at 468.2 K in a 25.0 L fuel combustion vessel if it contains 60.0 grams CO₂, 82.1 g
NeTakaya

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

  • Mass of CO₂ (m): 60.0 g
  • Volume of the vessel (V): 25.0 L
  • Temperature (T): 468.2 K

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

5 0
3 years ago
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