First find the names of the acids end in “acid”. Acid formulas have one of these forms: HX(aq) or HaXbOc then find the Ionic compounds that contain hydroxide. (OH-) , carbonate (CO32-) , or hydrogen carbonate (HCO3-) anions are basic.
Answer:
= 654.5 g NaNO3
Explanation:
Molarity = Moles/ volume
Volume = 3.5 L
Molarity = 2.2 M
Therefore;
Moles = Molarity × volume
= 3.5 L × 2.2 M
= 7.7 moles
But 1 mole of NaNO3 is 85 g/mol
Mass of NaNO3 = 85 g/mole × 7.7 moles
= 654.5 g NaNO3
