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PIT_PIT [208]
2 years ago
13

Which type of surface would most likely be the best reflector of electromagnetic energy?

Physics
1 answer:
Len [333]2 years ago
5 0
<span>light colored and smooth surface would most likely be the best reflector of electromagnetic energy.Light, shiny surfaces are the best reflectors of radiation and they will allow the waves to reflect and bounce off rather than absorb. we can consider mirror as the example ,it will only reflect the light energy falling on them and it will not absorb. The darker coloured and rough surfaced substances will definitely absorb some amount of light falling on it. so light coloured smooth or shiny surfaced material would be the best reflector for electromagnetic energy.</span>
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g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum decelerati
astraxan [27]

Given:

Initial speed of the motorcycle (u) = 35 m/s

Final speed of the motorcycle (v) = 0 m/s (Complete Stop)

Maximum deceleration of the motorcycle (a) = -1.2 m/s²

Required Equation:

\boxed{\bf{ v = u + at}}

Answer:

By substituting values in the equation, we get:

\rm \longrightarrow 0 = 35 + ( - 1.2)t \\  \\  \rm \longrightarrow  0 = 35 - 1.2t \\  \\  \rm  \longrightarrow 35 - 1.2t = 0 \\  \\  \rm  \longrightarrow 35- 35 - 1.2t = 0 - 35 \\  \\  \rm  \longrightarrow  - 1.2t =  - 35 \\  \\  \rm \longrightarrow  \dfrac{ - 1.2t}{ - 1.2}  =  \dfrac{ - 35}{ - 1.2}  \\  \\  \rm \longrightarrow  t = 29.167 \: s

\therefore Time taken by motorcycle to come to a complete stop (t) = 29.167 s

4 0
3 years ago
If you double the mass but don't change the net force what is the result on the acceleration
vazorg [7]
F is force, m is mass and a<span> is acceleration. The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.</span>
5 0
2 years ago
A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m
vfiekz [6]

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

5 0
3 years ago
What is the energy equivalent of an object with a mass of 4.1 kg?
siniylev [52]
To determine the energy equivalent of an object, we use the famous equation of Einstein which is E=mc^2 where m is the mass of the object and c is the speed of light (3x10^8 m/s). We calculate as follows:

E = mc^2
E = 4.1 kg (3x10^8 m/s)^2
E = 3.69x10^17 J
6 0
3 years ago
Read 2 more answers
Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle
LenKa [72]

Answer : The de-Broglie wavelength of this electron, 0.101\AA

Explanation :

The formula used for kinetic energy is,

K.E=\frac{1}{2}mv^2        ..........(1)

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{mv}

or,

v=\frac{h}{m\lambda}      ...........(2)

Now put the equation (2) in equation (1), we get:

\lambda=\frac{h}{\sqrt{2\times m\times K.E}}  ...........(3)

where,

\lambda = wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.11\times 10^{-31}Kg

K.E = kinetic energy = 4.71\times 10^{-15}J

Now put all the given values in the above formula (3), we get:

\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}

\lambda=1.0115\times 10^{-11}m=0.101\AA

conversion used : (1\AA=10^{-10}m)

Therefore, the de-Broglie wavelength of this electron, 0.101\AA

7 0
2 years ago
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