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maks197457 [2]
1 year ago
9

What graph would you use if you wanted to compare similar data for several individual items or events?

Chemistry
2 answers:
Soloha48 [4]1 year ago
5 0

Answer:

A. Bar graph

Explanation:

Bar graphs are used to compare things between different groups or to track changes over time. 

Lena [83]1 year ago
4 0

Answer:

option a, bar graph

Explanation:

- a graphic means of quantitative comparison by rectangles with lengths proportional to the measure of the data or things being compared

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Attempt 3 An irregular lump of an unknown metal has a measured density of 5.50 g/mL. The metal is heated to a temperature of 153
shepuryov [24]

Answer:

i think it's 20.0mL

Explanation:

i learned this question in class

4 0
3 years ago
Give three properties of a Solid
NARA [144]
In a solid, molecules are packed together, and it keeps its shape. Liquids take the shape of the container. Gases spread out to fill the container. Solid is one of the three main states of matter, along with liquid and gas.

Hope that helps!
8 0
3 years ago
When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha
schepotkina [342]
Missing question: 
Nitrogen: <span>2.0 L; </span>1.0 atm; 25°<span>C.
Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>
4 0
3 years ago
Read 2 more answers
What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
adell [148]

Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

⇒ with n = the number of moles O2 = 0.09975 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

⇒ with p = 0.958 atm

V = (0.09975 * 0.08206 * 295) / 0.958

V = 2.52 L

There is 2.52 L of O2 collected

7 0
3 years ago
Fan blades would be an analogy for which atomic model?
julia-pushkina [17]
I believe the correct answer from the choices listed above is option A. Fan blades would be an analogy for electron cloud model. Austrian physicist Erwin Schrödinger (1887-1961) developed an “Electron Cloud Model<span>” in 1926. It consisted of a dense nucleus surrounded by a cloud of electrons. Hope this helps.</span>
4 0
3 years ago
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