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Neporo4naja [7]
3 years ago
12

Determine how many grams of sodium phosphate would be needed to prepare 455 ml of a 2.50% (m/v) sodium phosphate solution

Chemistry
1 answer:
Arisa [49]3 years ago
8 0
When the m/v percentage has been given its weight / volume percentage. This means the mass of solute in g dissolved in 100 mL of solution.
the sodium phosphate solution to be prepared should have a 2.50 % (m/v) that means there should be 2.50 g of sodium phosphate in 100 mL solution.
then if 100 mL should contain - 2.50 g
then 455 mL should have - 2.50 / 100 x 455 = 11.6025 g
the mass of sodium phosphate required is 11.6 g
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Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

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Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

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Answer:

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Explanation:

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