Answer:
(A) 
(B) s = 146.664 m
Explanation:
We have given car starts from the rest so initial velocity u = 0 m /sec
Final velocity v = 88 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So 
Time is given t = 12 sec
(A) From first equation of motion v = u+at
So 
So acceleration of the car will be
(b) From third equation of motion 
So 
s = 146.664 m
Distance traveled by the car in this interval will be 146.664 m
Kinetic energy because the ball is in motion or moving with energy behind it... kinda like when you shoot a gun, the bullet is fired out of the muzzle with kinetic energy ( Punch ) and the bullet goes through a wall or something. Sorry but my math skills aren't very good to give complex calculations but I would recommend that you maybe talk to some of the top ranking math guys on the website. Maybe they can give you better help...
Anyways, I hope I have been helpful to you.
Answer:
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Explanation:
Answer:
1 kg
Explanation:
Applying,
Hook's law,
F = ke................. Equation 1
Where F = force, k = force constant of the spring, e = extension.
But from the question,
The weight of the bottle is the force acting on the spring scale
therefore,
mg = ke............ Equation 2
Where m = mass of the bottle, g = acceleration due to gravity.
make k the subject of the equation
k = mg/e............ Equation 3
Given: m = 0.5 kg, e = 1 cm = 0.01 m
Constant: g = 9.8 m/s²
k = (0.5×9.8)/0.01
k = 490 N/m
If the mass of the second bottle is weighed,
given: e = 2 cm = 0.02 m
subtitute into equation 1
m×9.8 = 490×0.02
9.8m = 9.8
m = 9.8/9.8
m = 1 kg.
Hence the mass of the second bottle is 1 kg
Calculate force of each car:
P1 = 900 kg x 12m/s = 10,800
P2= 600 x 24 = 14,400
Degree of travel = arctan(14,300/10800)
Degree of travel = 53.1 N of E
