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tigry1 [53]
3 years ago
10

A car initially going 61 ft/sec brakes at a constant rate (constant negative acceleration), coming to a stop in 7 seconds.

Physics
1 answer:
Bond [772]3 years ago
4 0

Answer:

See the attachment below for the graphics in part (a)

The initial velocity for this time interval is u = 61ft/sec and the final velocity is 0m/s because the car comes to a stop.

This a constant acceleration motion considering the given time interview over which the brakes are applied. So the equals for constant acceleration motion apply here.

Explanation:

The full solution can be found in the attachment below.

Thank you for reading. I hope this post is helpful to you.

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Hope this helps!
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What is the density of a rock that has a mass of 10 grams and the volume of 2ml?
tatiyna
It will be
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A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second; and the m
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Answer

given,                                                

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  = \dfrac{mv^2}{r}                          

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T =\dfrac{mv^2}{r}                                

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8 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

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D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

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Here,

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For small angle sin \theta = \theta

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L = \frac{d}{sin\theta}

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Therefore the distance is 5.367km.

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