Answer: The final temperature is equal to
45 Celsius
Explanation:
Explanation:
We have the amount of energy gain
Q
=
m
⋅
c
⋅
Δ
T
=
m
c
Δ
t
where
c
=
4.184
J
/
g
.
C
is the specific heat of water,
m
is the mass of water
⇒
840
=
10
x
4.184
⋅
(
t
−
25
)
t
=
840
10
x
4.184
+
25
=
45
i.e.
45
∘
C
A mixture of Cu2 and CuO of mass 8.828g is reduced to copper metal with hydrogen:
Cu2O + H2 --> 2Cu + H2O
CuO + H2 --> Cu + H2O
If the mass of pure copper isolated was 7.214g, determine the percent by mass of CuO in the original sample
Let x = grams of CuO in the original sample.
y = grams of Cu2O in the original sample.
Eq. #1 x + y = 8.828 grams
Molar mass of CuO = 63.5 + 16 = 79.5 grams
Moles of CuO = x ÷ 79.5
Molar mass of Cu2O = 63.546 + 32 = 95.5 grams
Moles of Cu2O = y ÷ 95.5
According to the 2nd balanced equation, CuO + H2 --> Cu + H2O ,
1 mole of CuO produces 1 mole of Cu.
So, x ÷ 79.5 moles of CuO will produce x ÷ 79.5 moles of Cu
According to the 1st balanced equation, Cu2O + H2 --> 2Cu + H2O,
1 mole of Cu2O produces 2 moles of Cu
So, (y ÷ 95.5) moles of Cu2O will produce 2 * (y ÷ 95.5) moles of Cu
Since, the mass of pure copper isolated was 7.214 grams
Moles of Cu = (7.214 ÷ 63.5)
Moles of Cu from Cu2O + moles of Cu from CuO = total moles of Cu!!
2 * (y ÷ 95.5) + (x ÷ 79.5) = (7.214 ÷ 63.5)
Multiply by both sides by 95.5 * 79.5 * 63.5 to get rid of denominators
(2 * 79.5 * 63.5) y + (95.5 * 63.5) x = (7.214 * 95.5 * 79.5)
10,096.5 y + 6,064.25 x = 36,418.0755
Divide both sides by 6,064.25
x + 1.665 y = 6
Eq.#2 x = 6 – 1.665 y
Eq. #1 x + y = 8.828
x = 8.828 – y
8.828 – y = 6 – 1.665 y
0.665 y = 2.828
y = 4.25 grams of Cu2O
x = 8.828 – 4.25 = 4.58 grams of CuO
% CuO = (4.58 ÷ 8.828) * 100 = 51.88% CuO
Answer:
When designers require rugged, tough materials for their projects, steel and titanium are the first options that come to mind. These metals come in a wide assortment of alloys - base metals imbued with other metallic elements that produce a sum greater than its parts. There are dozens of titanium alloys and hundreds more steel alloys, so it can oftentimes be challenging to decide where to begin when considering these two metals. This article, through an examination of the physical, mechanical, and working properties of steel and titanium, can help designers choose which material is right for their job. Each metal will be briefly explored, and then a comparison of their differences will follow to show when to specify one over the other.
Explanation:
in the ph. above
Answer:
Explanation:
Here, we want to get the volume of the nitrogen gas at the lower temperature
From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion
The mathematical relationship is:
Where:
V1 is the initial volume which is 410 L
V2 is the final volume which is unknown
T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K
T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K
Substituting the values, we have it that:
