Answer:
34 square units
Step-by-step explanation:
The figure can be considered to be a trapezoid with a rectangle removed.
The area of the trapezoid is ...
A = (1/2)(b1 +b2)h
A = (1/2)(10 +6)(5) = 40
The area of the rectangle is ...
A = LW
A = (3)(2) = 6
Then the area of the shaded portion of the figure is ...
shaded area = trapezoid area - rectangle area
= 40 - 6 = 34 . . . square units
9 - 6 + 4 - 8/3 ..,
geometric series a(n) = a1r^(n-1)
r = a(n+1)/a(n)
-6/9 = -2/3
4/-6 = -2/3
-8/3/4 = -2/3
so r = -2/3 and a1 = 9
Sn = a1(1-r^n)/(1-r) = 9(1-(-2/3)^n)/(1-(-2/3))
n is infinite Sn = 9/(5/3) = 27/5
Answer:
18ft
Step-by-step explanation:
6ft -> 4ft shadow
6 = 4m
m = 6/4
y = 12m
y = 12(6/4)
y = 18ft
