A child is stationary on a swing. The child is given a push by his brother to start him swinging. His brother applies a steady f
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Answer:
(a) change in the internal energy of the gas is zero
(b) the work done by the gas is 16.93 kJ
(c) the heat flow is 16.93 kJ, which is into the gas
Explanation:
Given;
number of moles of gas, n = 6.35 moles
temperature of the gas, T = 320 K
initial volume of the gas, V₁ = 1.45 L
final volume of the gas, V₂ = 3.95 L
Part (a)
For isothermal expansion, temperature is constant and internal energy will also be constant.
Therefore, change in the internal energy of the gas is zero since the gas expanded isothermally (constant temperature).
ΔU = Q - W
where;
ΔU is change in internal energy
Q is heat transferred to the system
W is the work done by the system
Thus, Q = W
ΔU = 0
Part (b)
the work done by the gas
where;
R is gas constant = 8.314 J/mol.K
Part (c)
the heat flow into or out of the gas
Q = ΔU + W
Q = 0 + 16.93 kJ
Q = 16.93 kJ
Since the heat flow is positive, then it is heat flow into the gas.