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Serggg [28]
2 years ago
14

A 2.0-kilogram cantaloupe rolling north at 4.0 meters per second collides head on with a 1.0-kilogram orange rolling south at 8.

0 meters per second. What is the magnitude of the total momentum of the two fruit?
Physics
2 answers:
Murrr4er [49]2 years ago
8 0

Answer:

Hi how are you doing today Jasmine

Nat2105 [25]2 years ago
7 0

Answer:

16kg*m/s

Explanation:

a)p=m*v=2*4=8kg-m/s

b)p=m*v=1*8=8kg-m/s

add them

=16kg-m/s

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Answer:

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To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution.  By definition is defined as:

\theta = 1.22\frac{\lambda}{d}

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Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

r = l\theta

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r = l(\frac{1.22\lambda}{d})

r = 1.22\frac{l\lambda}{d}

Replacing with our values we have that,

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