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Alexxx [7]
3 years ago
12

The regular price of a smart phone is represented by x. When an upgraded phone is released, the new price is 25% more than the o

lder model. The upgraded phone's price can be represented by which expression?
A) .25x
Eliminate
B) 1.25x
C) 1.75x
D) x + .75x
Mathematics
2 answers:
Alex73 [517]3 years ago
6 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

Regular price of a smart phone  be x

According to question, the new price is 25% more than the older model.

So, New price becomes

\frac{100+25}{100}\times x\\\\=\frac{125}{100}\times x\\\\=1.25\times x\\\\=1.25x

The upgraded phone's price can be represented by 1.25x.

Hence, Option 'B' is correct.

VARVARA [1.3K]3 years ago
3 0
1.25x

because 25% can be represented as 0.25. so as the new price would be 125% of the old one its 1.25x
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I assume the heights are 160 ft and 1480 ft.

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Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.

Now we add our two heights to find the total height.

h + h + 160 is the total height.
We can write it as 2h + 160

We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.

2h + 160 = 1480

Subtract 160 from both sides

2h = 1320

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3 years ago
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Step-by-step explanation:

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Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

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P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

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= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

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= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

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3 years ago
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Romashka-Z-Leto [24]
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3 years ago
Find the slope of a line perpendicular to y = 3x + 7
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Answer:

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Step-by-step explanation:

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3 years ago
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