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ivolga24 [154]
1 year ago
5

Why is the mass of the third subatomic particle ignored?

Chemistry
1 answer:
dmitriy555 [2]1 year ago
3 0

Answer: The mass of electrons is mostly ignored because electrons are extremely small compared to neutrons and protons.

Explanation: A proton is about 1,836 times the size of an electron.

On the periodic table, the atomic number for each element can be found. This number is found by measuring the weight of 6.02 x 10^23 atoms of the element in grams. Electrons aren't ignored when finding exact math, but for the sake of simplification high school teachers will generally have you only count the number of protons and neutrons when calculating the mass of atoms.

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A buret is used to dispense standardized NaOH solution. The initial buret reading is 2.73 mL, and after dispensing a known volum
Novosadov [1.4K]

Answer:

1.62x10⁻³ moles of NaOH were dispensed

Explanation:

Molarity is an unit in chemistry defined as the ratio between moles of solute (In the problem, NaOH), per liter of solution.

The concentration of the solution is 0.125moles per liter. That means 1L of solution has 0.125 moles of NaOH.

The volume you dispensed in the buret was:

15.67mL - 2.73mL =

12.94mL of the 0.125M NaOH are:

12.94mL = 0.01294L * (0.125moles / L) =

<h3>1.62x10⁻³ moles of NaOH were dispensed</h3>
3 0
3 years ago
It takes 42.25 ml of 0.0500 M Na2S2O3 solution to completely react with the iodine present in a 150.0 ml iodine solution. How ma
svlad2 [7]

Answer:

There were 0.268 grams I2 present

Explanation:

Step 1: Data given

Volume of Na2SO3 = 42.25 mL = 0.04225 L

Molarity of Na2SO3 = 0.0500 M

Volume of iodine = 150.0 mL

Step 2: The balanced equation

I2 + 2 Na2SO3 → Na2S2O6 + 2 NaI

Step 3: Calculate moles of Na2SO3

Moles Na2SO3 = molarity * volume

Moles Na2SO3 = 0.0500 M * 0.04225 L

Moles Na2SO3 = 0.0021125 moles

Step 4: Calculate moles I2

For 1 mol I2 we need 2 moles Na2SO3

For 0.0021125 moles Na2SO3 we have 0.00105625

Step 5: Calculate mass of I2

Mass I2 = moles * molar mass

Mass I2 = 0.00105625 * 253.8 g/mol

Mass I2 = 0.268 grams

There were 0.268 grams I2 present

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Answer:

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The process of heating oil to separate out its various components is called __
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The answer is refining which is c

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The answer is D. CaCl2 and H2O
6 0
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