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1 year ago

What does the remainder theorem conclude given that f(x)/x+3 has a remainder of 11?

1 answer:

8 0

The conclusion of the remainder theorem about a situation where a function; f(x) is divided by (x+3) and has a remainder of 11 is that; f(-3) = 11.

<h3>What does the remainder theorem conclude given that f(x)/x+3 has a remainder of 11?</h3>

It follows from the task content that f(x)/x+3 has a remainder of 11.

On this note, it follows from the remainder theorem regarding the division of polynomials that; when; x + 3= 0; x = -3 and hence;

f(-3) = 11.

Ultimately, the inference that can be drawn from the remainder theorem statement as in the task content is; f(-3) = 11.

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FrozenT [24]

Answer: Choice D

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Explanation:

The formula for the surface area of a cylinder is

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So that's how we get to

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18. What is the area of a piece of garden plot 5 yards 2 feet long by 6 yards 1 foot wide? Give your answer in square feet.

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Answer:

Step-by-step explanation:

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2 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

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3 years ago

If (2x - 3) is a factor of mx^2 - 11x - 6, find the other factor.

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Step-by-step explanation:

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2 years ago