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marusya05 [52]
1 year ago
8

Calculate the concentration expressed in percent, if 10 g of NaOH is diluted to 500 ml with water.

Chemistry
1 answer:
Zepler [3.9K]1 year ago
5 0

If 10 g of NaOH is diluted to 500 ml with water then  the concentration expressed in percent is 0.5 mol/L .

Calculation ,

Given mass in gram = 10 g

Number of moles = given mass /molar mass = 10 g / 40 g/mol = 0.25mole

Given volume in ml = 500 ml

Given volume in liter  = 0.5 L

Putting the value of mass and volume in equation i we get concentration expressed in percent .

C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L

C  =  0.5 mol/L

Concentration of solution in terms of percentage can be expressed in two ways

1) percentage by mass

2) percentage by volume

Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.  

To learn more about concentration please click here ,

brainly.com/question/10380236

#SPJ4

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either a car or a rock

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If an atom has 15 protons and a mass of 31 how many neutrons will it have
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16 neutrons

Explanation:

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2 years ago
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What is the mass of 0.80 moles of Mg? (1 point)
Aneli [31]

Answer:

m = 19 grams

Explanation:

Given that,

No. of moles, n = 0.8

The molar mass of magnesium, M = 24.305 u

We need to find the mass of 0.80 moles of Mg. We know that given mass to the molar mass is equal to no of moles. Let the mass is m. So,

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=0.8\times 24.305 \\\\m=19.444\ \text{grams}

or

m = 19 grams

So, the mass of 0.8 moles of Mg is 19 grams.

6 0
3 years ago
The rate of effusion of nitrogen gas (N2) is 1.253 times faster than that of an unknown gas. What is the molecular weight of the
ollegr [7]

Answer:

43.96

Explanation:

Graham's law was applied and the rates of effusion of nitrogen and the unknown gas were compared as shown in the image. The unknown gas is heavier than hydrigen hence it effuses slower than hydrogen as anticipated by Graham's law.

5 0
3 years ago
Consider the insoluble compound cobalt(II) carbonate , CoCO3 . The cobalt(II) ion also forms a complex with ammonia . Write a ba
Cloud [144]

Answer:

7.7×10^-6

Explanation:

CoCO3(s)<--------> Co^2+(aq) + CO3^2-(aq) Ksp= 1.0 ×10 ^-10

Co^2+(aq) + 6NH3(aq) <-----------> [Co(NH3)6]^2+. Kf = 7.7×10^4

Overall:

CoCO3(s) + 6NH3(aq) <--------> [Co(NH3)6]^2+(aq) + CO3^2-(aq) Knet= Ksp× Kf

Knet= Ksp× Kf = 1.0 ×10 ^-10 ×7.7×10^4= 7.7×10^-6

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