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vovangra [49]
3 years ago
11

4. When benzene reacts with 1-chloro-2,2-dimethylpropane (neopentyl chloride) in the presence of aluminum chloride, the major pr

oduct is 2-methyl-2-phenylbutane, not 2,2-dimethyl-1- phenylpropane (neopentylbenzene). Explain this result

Chemistry
1 answer:
BARSIC [14]3 years ago
8 0

Answer:

Explanation:

In this case, we have a <u>Friedel-Craft reaction</u> (see figure 1). Usually in this type of reaction, the benzene ring is <u>bonded directly to the carbon that has the halide atom</u>. But in this specific case, this is not happening.

To understand why we have to remember the reaction mechanism of this reaction. As first, step the Cl-C bond attacks the AlCl_3 and we form a new bond between the alkyl halide and the AlCl_3, finally the C-Cl bond is broken and a <u>carbocation is formed</u>. In this case, we will have a primary carbocation, a very <u>unstable species</u>. Therefore we will have a <u>methyl shift</u> to obtain a tertiary carbocation.

This tertiary carbocation will react with and continues the reaction. (See figure 2)

I hope it helps!

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Write the following numbers in standard notation. Use a terminal decimal point when needed.
maw [93]

In this case, when converting scientific notation to standard notation, we simply have to multiply the given number by 10^{x}x.

The answer will be 7.510^{2}  = 7.5100 = 750

A standard notation is a form of writing a given number, an equation, or an expression in a form that follows certain rules. For example, 4.5 billion years is written as 4,500,000,000 years.

Learn more about standard notation here:

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8 0
1 year ago
At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5
Annette [7]

Answer:

4600s

Explanation:

2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

-\frac{d[B]}{dt}=k[B] - - -  -\frac{d[B]}{[B]}=k*dt

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.  

-\frac{d[P(B)]}{P(B)}=k*dt  

-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt

Integrating we get:

\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt

-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})

Clearing for t2:

\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}

ln[P(N_{2}O_{5})]=ln(650)=6.4769

ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333

t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s

4 0
3 years ago
The structural form of the element Ge closely resembles the structure of A. C (diamond) B. N (diatomic) C. As (tetrahedral) D. S
Ksivusya [100]

The structural form of the element Ge closely resembles the structure of C (diamond).

Diamond is composed of a lattice structure in which atoms of carbon are held together in a face centered cubic lattice.

Germanium, an element in the same group as carbon also forms a face centered cubic lattice that is very similar to that of diamond.

Hence, the  structural form of the element Ge closely resembles the structure of C (diamond).

Learn more: brainly.com/question/14578576

6 0
3 years ago
Identify the property of the matter described below.
ZanzabumX [31]

Answer: C.

Explanation: Alcohol floats on oil and water sinks in oil. Water, alcohol, and oil layer well because of their densities, but also because the oil layer does not dissolve in either liquid. The oil keeps the water and alcohol separated so that they do not dissolve in one another. ... Water sinks because it is more dense than oil.

7 0
3 years ago
A solution contains 90 milliequivalents of HC1 in 450ml. What is its normality?
Rashid [163]

Answer:

Normality N = 0.2 N

Explanation:

Normality is the number of gram of equivalent of solute divided of volume of solution, where the number of gram of equivalent of solute is weight of the solute divided by the equivalent weight.

Normality is represented by N.

Mathematically, we have :

\mathbf{Normality \ N = \dfrac{Number \ of \ gram \of \ equivalent\  of\  solute }{volume \ of \ solution}}

Given that:

number of gram of equivalent of solute = 90 milliequivalents 90 × 10⁻³ equivalent

volume of solution (HCl) = 450 mL 450 × 10⁻³ L

\mathbf{Normality \ N = \dfrac{90 \times 10^{-3}}{450 \times 10^{-3}}}

Normality N = 0.2 N

7 0
3 years ago
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