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strojnjashka [21]

9 months ago

9

❌❌PLEASE HELPILL MARK BRAINLIEST❌❌❌Does coordinate m or coordinate n represent a greater number in the following parallelogram?

1 answer:

Maru [420]9 months ago

4 0

Answer:

The answer would be m.

Step-by-step explanation:

The point would be (7,1) If you look at the top two points, (3,5) and (10,5) You can see that the y coordinates are the same. They are both 5. So on the bottom left (0,1) we know that are n will be 1 . Now we have to figure out m. If we look on the top (3,5) (10,5) We can see from the x's 10 and 3, that they are a distance of 7 apart. Since our bottom left hand corner is (0,1) If we add 7 to 0 we get 7. That makes m equal 7

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A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 7 grams and the amo

OlgaM077 [116]

Answer:

3 necklaces and 12 bracelets

Step-by-step explanation:

Bracelets = x +4

amount of necklace gold = 20*x

amount of gold in bracelet = 7*(x+4)

added together = 109 gm

20x + 7(x+4) = 109

20x + 7x+28 = 109

27x+28=109

-28 -28

27x= 81

/27 /27

x=3 necklaces

then bracelets = 3+4=12

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2 years ago

Una caja de fideos de 7.2 onzas a 0.67 o una caja de fideos de 13 onzas a 1.28 cual tiene el mejor precio

uysha [10]

Answer:

The first one. Brainly is also in spanish

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2 years ago

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

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Serggg [28]

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I hope this helped.

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