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Olegator [25]
2 years ago
13

I need some help with this,, anyone??It's has three parts so... (9A), (9B), and (9C)

Physics
1 answer:
Readme [11.4K]2 years ago
5 0
A is 588N.

b) When she reaches her terminal speed, 10 seconds into the dive, she is no longer accelerating, so the net force on her is zero.
Think of it this way: If the net force were not zero she would continue to accelerate.

c) She is no longer accelerating.
Her acceleration is zero.
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Answer:

0.1 s

Explanation:

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F - μmg = ma

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So, substituting the values of the variables into the equation, we have

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a = 2850 N/300 kg - 0.45 × 9.8 m/s²

a = 9.5 m/s² - 4.41 m/s²

a = 5.09 m/s²

Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.

So, making t subject of the formula, we have

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substituting the values of the variables into the equation, we have

t = (v - u)/a

t = (0.5 m/s - 0 m/s)/5.09 m/s²

t = 0.5 m/s ÷ 5.09 m/s²

t = 0.098 s

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