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konstantin123 [22]
1 year ago
11

Identify the Lewis acid and Lewis base in each reaction:Fe³⁺ + 2H₂O ⇄ FeOH²⁺ + H₃O⁺

Chemistry
1 answer:
yan [13]1 year ago
4 0

In the given reaction Fe³⁺ + 2H₂O ⇄ FeOH²⁺ + H₃O⁺ Lewis acid is Fe³⁺ and the Lewis base is H₂O.

<h3>What is a Lewis acid and Lewis base?</h3>
  • According to the Lewis theory of acid-base reactions, acids accept pairs of electrons and bases donate pairs of electrons.
  • Any substance like H+ ion, which is capable of accepting a pair of nonbonding electrons or an electron-pair acceptor is known as a Lewis acid.
  • Any substance, like the OH- ion, that is capable of donating a pair of nonbonding electrons or an electron-pair donor is a Lewis base.
  • From the Lewis theory, with no change in the oxidation numbers of any atoms, acids react with bases to share a pair of electrons.

To learn more about Lewis acid-base reactions: brainly.com/question/14861040  

#SPJ4                                                                                                

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Answer:

The answer to your question is B. metallic

Explanation:

Covalent bonding is a bond between two nonmetals and the difference in electronegativity is between 0 and 1.7. Sodium could not have this kind of bond because is a metal.

Ionic bonding is a bond between a metal and a nonmetal and the difference of electronegativity is higher than 1.7. Sodium can have this kind of bond it is necessary one nonmetal.

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3 years ago
How many grams of NH3 can be produced from 2.30 mol of N2 and excess H2.
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<h3>Answer:</h3>

78.34 g

<h3>Explanation:</h3>

From the question we are given;

Moles of Nitrogen gas as 2.3 moles

we are required to calculate the mass of NH₃ that may be reproduced.

<h3>Step 1: Writing the balanced equation for the reaction </h3>

The Balanced equation for the reaction is;

   N₂(g) + 3H₂(g) → 2NH₃(g)

<h3>Step 2: Calculating the number of moles of NH₃</h3>

From the equation 1 mole of nitrogen gas reacts to produce 2 moles of NH₃

Therefore, the mole ratio of N₂ to NH₃ is 1 : 2

Thus, Moles of NH₃ = Moles of N₂ × 2

                                  = 2.3 moles × 2

                                  = 4.6 moles

<h3>Step 3: Calculating the mass of ammonia produced </h3>

Mass = Moles × molar mass

Molar mass of ammonia gas = 17.031 g/mol

Therefore;

Mass = 4.6 moles × 17.031 g/mol

         = 78.3426 g

         = 78.34 g

Thus, the mass of NH₃ produced is 78.34 g

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