Solution,
Mass of Mg - 21gm
molar mass of Mg - 24gm
moles = Given mass/ Molar mass
moles = 21/24 = 0.875
1 mole of Mg produce 1 mole of H2 gas
so 0.875 mole of Mg will produce 0.875 moles of H2 gas
One mole of H2 gas = 22.4 litre
0.875 mole of H2 gas = 0.875×22.4
0.875 mole of H2 gas = 19.60 litre
So the nearest ANSWER is Option four 19.37 litre.
Answer:
a. 10.54
Explanation:
reaction is
NH₃ + NaOH -----------------NH₄Cl + H₂O
0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl
mol NH₃ = 0.80 - 010 = .70
mol NH₄Cl = 0.80 + .10 = 0.90
pH = pKₐ + log (( NH₃/NH₄Cl))
pH = 9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54
Answer:
False
Explanation:
On the left side of the equation (Li + O2), there is 1 Li atom and 2 O atoms.
but on thw right side of the equation (Li2O,) there is 2 Li atoms and 1 O atom
<span>6.03 moles.
1 molecule of butane contains 4 carbon atoms and ten hydrogen atoms.
The molar mass is 4 times the atomic mass of carbon, 12 g/mol, plus 10 times the atomic weight of hydrogen, 1 g/mol.
Molar mass = 4 * 12 g/mol + 10 * 1 g/mol = 58 g/mol.
This means that 1 mole of butane has a mass of 58 g.
To figure out how many moles are in a sample of butane, divide the mass of sample in grams by 58 grams
Number of moles in sample = 350 g / 58 g/mol = 6.03 moles.</span>
